ZOJ Problem Set–1970 All in All

Time Limit: 2 Seconds      Memory Limit: 65536 KB


You have devised a new encryption technique which encodes a message by inserting between its characters randomly generated strings in a clever way. Because of pending patent issues we will not discuss in detail how the strings are generated and inserted into the original message. To validate your method, however, it is necessary to write a program that checks if the message is really encoded in the final string.

Given two strings s and t, you have to decide whether s is a subsequence of t, i.e. if you can remove characters from t such that the concatenation of the remaining characters is s.

Input

The input contains several testcases. Each is specified by two strings s, t of alphanumeric ASCII characters separated by whitespace. Input is terminated by EOF.

Output

For each test case output, print "Yes" if s is a subsequence of t or "No" if not.

Sample Input

sequence subsequence
person compression
VERDI vivaVittorioEmanueleReDiItalia
caseDoesMatter CaseDoesMatter

Sample Output

Yes
No
Yes
No


Source: University of Ulm Local Contest 2002

  1: #include<iostream>
  2: #include<string>
  3: using namespace std;
  4: int main(void)
  5: {
  6:   string s,t;
  7:   while(cin>>s>>t)
  8:   {
  9:     int preIndex = -1;
 10:     bool no = false;
 11:     for(int i = 0; i < s.length(); i++)
 12:     {
 13:       int index = t.find_first_of(s[i], preIndex + 1);
 14:       if(index == string::npos)
 15:       {
 16:         cout<<"No"<<endl;
 17:         no = true;
 18:         break;
 19:       }
 20:       preIndex = index;
 21:     }
 22:     if(!no)
 23:       cout<<"Yes"<<endl;
 24:   }
 25:   return 0;
 26: }
posted @ 2012-05-10 15:43  Gavin Lipeng Ma  阅读(340)  评论(0编辑  收藏  举报