2.3.5 Controlling Companies

Controlling Companies

Some companies are partial owners of other companies because they have acquired part of their total shares of stock. For example, Ford owns 12% of Mazda. It is said that a company A controls company B if at least one of the following conditions is satisfied:

  • Company A = Company B
  • Company A owns more than 50% of Company B
  • Company A controls K (K >= 1) companies denoted C1, ..., CK with each company Ci owning xi% of company B and x1 + .... + xK > 50%.

Given a list of triples (i,j,p) which denote company i owning p% of company j, calculate all the pairs (h,s) in which company h controls company s. There are at most 100 companies.

Write a program to read the list of triples (i,j,p) where i, j and p are positive integers all in the range (1..100) and find all the pairs (h,s) so that company h controls company s.

PROGRAM NAME: concom

INPUT FORMAT

Line 1: n, the number of input triples to follow
Line 2..n+1: Three integers per line as a triple (i,j,p) described above.

SAMPLE INPUT (file concom.in)

3
1 2 80
2 3 80
3 1 20

OUTPUT FORMAT

List 0 or more companies that control other companies. Each line contains two integers that denote that the company whose number is the first integer controls the company whose number is the second integer. Order the lines in ascending order of the first integer (and ascending order of the second integer to break ties). Do not print that a company controls itself.

SAMPLE OUTPUT (file concom.out)

1 2
1 3
2 3


{
ID: makeeca1
PROG: concom
LANG: PASCAL
}
program concom;
const maxn=100;
var n,m:longint;
    map:array[0..maxn,0..maxn]of longint;
    c:array[0..maxn]of longint;
    b:array[0..maxn]of boolean;
function max(xx,yy:longint):longint;
begin if xx>yy then exit(xx)else exit(yy);end;
procedure init;
var x,y,z,i:longint;
begin
  readln(m);
  for i:=1 to m do
  begin
    readln(x,y,z);
    n:=max(n,max(x,y));
    map[x,y]:=z;
  end;
end;
procedure dfs(x:longint);
var i:longint;
begin
  b[x]:=true;
  for i:=1 to n do inc(c[i],map[x,i]);
  for i:=1 to n do
  if (c[i]>50) and not b[i]then dfs(i);
end;
procedure work;
var i,j:longint;
begin
  for i:=1 to n do
  begin
    fillchar(c,sizeof(c),0);
    fillchar(b,sizeof(b),0);
    dfs(i);
    for j:=1 to n do
     if (i<>j)and(c[j]>50)then writeln(i,' ',j);
  end;
end;
begin
  assign(input,'concom.in');reset(input);
  assign(output,'concom.out');rewrite(output);
  init;
  work;
  close(output);
end.

 

posted on 2013-08-22 12:15  makeecat  阅读(186)  评论(0编辑  收藏  举报