如何在TypeScript中为对象动态分配属性?

本文翻译自:How do I dynamically assign properties to an object in TypeScript?

If I wanted to programatically assign a property to an object in Javascript, I would do it like this: 如果我想以编程方式将属性分配给Javascript中的对象,则可以这样做:

  1.  
    var obj = {};
  2.  
    obj.prop = "value";

But in TypeScript, this generates an error: 但是在TypeScript中,这会产生一个错误:

The property 'prop' does not exist on value of type '{}' 类型“ {}”的值不存在属性“ prop”

How am I supposed to assign any new property to an object in TypeScript? 我应该如何在TypeScript中为对象分配任何新属性?


#1楼

参考:https://stackoom.com/question/RkGB/如何在TypeScript中为对象动态分配属性


#2楼

Although the compiler complains it should still output it as you require. 尽管编译器抱怨它仍应按您的要求输出。 However, this will work. 但是,这将起作用。

  1.  
    var s = {};
  2.  
    s['prop'] = true;

#3楼

您可以添加此声明以使警告静音。

declare var obj: any;


#4楼

Or all in one go: 或一劳永逸:

  1.  
    var obj:any = {}
  2.  
    obj.prop = 5;

#5楼

I tend to put any on the other side ie var foo:IFoo = <any>{}; 我倾向于把any放在另一边,即var foo:IFoo = <any>{}; So something like this is still typesafe: 所以像这样的东西仍然是类型安全的:

  1.  
    interface IFoo{
  2.  
    bar:string;
  3.  
    baz:string;
  4.  
    boo:string;
  5.  
    }
  6.  
     
  7.  
    // How I tend to intialize
  8.  
    var foo:IFoo = <any>{};
  9.  
     
  10.  
    foo.bar = "asdf";
  11.  
    foo.baz = "boo";
  12.  
    foo.boo = "boo";
  13.  
     
  14.  
    // the following is an error,
  15.  
    // so you haven't lost type safety
  16.  
    foo.bar = 123;

Alternatively you can mark these properties as optional: 另外,您可以将这些属性标记为可选:

  1.  
    interface IFoo{
  2.  
    bar?:string;
  3.  
    baz?:string;
  4.  
    boo?:string;
  5.  
    }
  6.  
     
  7.  
    // Now your simple initialization works
  8.  
    var foo:IFoo = {};

Try it online 在线尝试


#6楼

Store any new property on any kind of object by typecasting it to 'any': 将任何新属性存储在任何类型的对象上,方法是将其类型转换为“ any”:

  1.  
    var extend = <any>myObject;
  2.  
    extend.NewProperty = anotherObject;

Later on you can retrieve it by casting your extended object back to 'any': 稍后,您可以通过将扩展对象转换回'any'来检索它:

  1.  
    var extendedObject = <any>myObject;
  2.  
    var anotherObject = <AnotherObjectType>extendedObject.NewProperty;
posted @ 2020-11-06 10:19  追求极致  阅读(4946)  评论(0编辑  收藏  举报