POJ 3176 Cow Bowling
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/**************************************
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Problem: POJ 3176 Cow Bowling
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Time: 32MS
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Memory: 4120K
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Accepted Time: 2009-04-11 12:38:54
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Tips:《程序设计导引及在线实践》10.1
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**************************************/
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#include <stdio.h>
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int main()
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{
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int n;
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while(scanf("%d",&n)!=EOF)
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{
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int a[1009][1009],i,j;
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for(i=1;i<=n;i++)
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for(j=1;j<=i;j++)
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scanf("%d",&a[i][j]);
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int b[1009];
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for(i=1;i<=n;i++)b[i]=a[n][i];
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for(i=n-1;i>=1;i--)
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{
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for(j=1;j<=i;j++)
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if(b[j]>b[j+1])
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{
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b[j]=b[j]+a[i][j];
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}
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else
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{
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b[j]=b[j+1]+a[i][j];
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}
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}
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printf("%d\n",b[1]);
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}
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return 0;
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}
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