HEU 5001 Inversion
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/**************************************
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Problem: HEU 5001 Inversion
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Time: 0.0000 s
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Memory: 240 k
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Accepted Time: 2009-03-28 12:57:21
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Tips: 数字排列
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**************************************/
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#include <stdio.h>
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#include <string.h>
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int main()
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{
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int n;
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while(1)
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{
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scanf("%d",&n);
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if(n==0)break;
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char ch[5];
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int i,j,a[60],b[60];
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scanf("%s",ch);
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for(i=0;i<n;i++)scanf("%d",&a[i]);
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if(ch[0]=='P')
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{
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for(i=0;i<n;i++)
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{
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int count=0;
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for(j=0;;j++)
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{
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if(a[j]>i+1)count++;
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else if(a[j]==i+1)break;
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}
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b[i]=count;
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}
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}
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else
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{
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bool c[60];
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memset(c,1,sizeof(c));
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for(i=0;i<n;i++)
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{
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j=0;
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int count=0;
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while(j!=a[i])
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{
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if(c[count++])j++;
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}
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while(!c[count])count++;
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b[count]=i+1;
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c[count]=0;
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}
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}
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for(i=0;i<n-1;i++)printf("%d ",b[i]);
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printf("%d\n",b[i]);
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}
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return 0;
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}
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