poj 3461 Oulipo

Time Limit:1000MS   Memory Limit:65536K
Total Submissions:45636   Accepted:18224

Description

The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter'e'. He was a member of the Oulipo group. A quote from the book:

Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…

Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive'T's is not unusual. And they never use spaces.

So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A','B','C', …,'Z'} and two finite strings over that alphabet, a wordWand a textT, count the number of occurrences ofWinT. All the consecutive characters of W must exactly match consecutive characters ofT. Occurrences may overlap.

Input

The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:

  • One line with the wordW, a string over {'A','B','C', …,'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the stringW).
  • One line with the textT, a string over {'A','B','C', …,'Z'}, with |W| ≤ |T| ≤ 1,000,000.

Output

For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the wordWin the textT.

Sample Input

3
BAPC
BAPC
AZA
AZAZAZA
VERDI
AVERDXIVYERDIAN

Sample Output

1
3
0
题意:
给你两个字符串,求第二个字符串在第一个字符串中
出现的次数。
 1 #include<iostream>
 2 #include<cstdio>
 3 #include<algorithm>
 4 #include<cmath>
 5 #include<cstring>
 6 #include<string>
 7 using namespace std;
 8 const int N=1e6+90;
 9 char s1[N],s2[N];
10 int T,len1,ans,len2,ne[N],i,j;
11 void kmp()
12 {
13     for(int i=1;i<=len2;++i) ne[i]=0;
14     for(int i=2;i<=len2;++i)
15     {
16         j=ne[i-1];
17         while(j && s2[i]!=s2[j+1]) j=ne[j];
18         if(s2[i]==s2[j+1]) ne[i]=j+1;
19     }
20     j=0;
21     for(int i=1;i<=len1;++i)
22     {
23         while(j && s1[i]!=s2[j+1]) j=ne[j];
24         if(s1[i]==s2[j+1]) j=j+1;
25         if(j==len2) ans++;
26     }
27 }
28 int main()
29 {
30     scanf("%d",&T);
31     while(T--)
32     {
33         scanf("%s%s",s2+1,s1+1);
34         len1=strlen(s1+1);len2=strlen(s2+1);
35         ans=0;
36         kmp();
37         printf("%d\n",ans);
38     }
39     return 0;
40 }/*
41 Sample Input
42 
43 3
44 BAPC
45 BAPC
46 AZA
47 AZAZAZA
48 VERDI
49 AVERDXIVYERDIAN
50 Sample Output
51 
52 1
53 3
54 0
55 */
View Code

 



posted @ 2018-03-13 16:32  月亮茶  阅读(133)  评论(0编辑  收藏  举报