摘要: SELECT a.address,a.cont AS countAddress,b.sum AS sumAddress,CONCAT( ROUND( a.cont / b.sum * 100, 2 ), '', '%' ) AS percent FROM( SELECT address, COUNT 阅读全文
posted @ 2021-05-15 08:57 凌波漫步~ 阅读(939) 评论(0) 推荐(0) 编辑