一起手写吧!实现一个Lazyman!

设计 LazyMan 类,实现以下功能

实现一个LazyMan,可以按照以下方式调用:
LazyMan('Hank')输出:
Hi! This is Hank!

LazyMan('Hank').sleep(10).eat('dinner')输出
Hi! This is Hank!
//等待10秒..
Wake up after 10
Eat dinner~

LazyMan('Hank').eat('dinner').eat('supper')输出
Hi This is Hank!
Eat dinner~
Eat supper~

LazyMan('Hank').sleepFirst(5).eat('supper')输出
//等待5秒
Wake up after 5
Hi This is Hank!
Eat supper
以此类推。

下面是 ES6 的实现方式,如果用 ES5 来写要在维护 this 方面多写一些代码。

class _LazyMan {
  constructor(name) {
    this.tasks = [];
    const task = () => {
      console.log(`Hi! This is ${name}`);
      this.next();
    }
    this.tasks.push(task);
    setTimeout(() => {               // 把 this.next() 放到调用栈清空之后执行
      this.next();
    }, 0);
  }

  next() {
    const task = this.tasks.shift(); // 取第一个任务执行
    task && task();
  }

  sleep(time) {
    this._sleepWrapper(time, false);
    return this;                     // 链式调用
  }

  sleepFirst(time) {
    this._sleepWrapper(time, true);
    return this;
  }

  _sleepWrapper(time, first) {
    const task = () => {
      setTimeout(() => {
        console.log(`Wake up after ${time}`);
        this.next();
      }, time * 1000)
    }
    if (first) {
      this.tasks.unshift(task);     // 放到任务队列顶部
    } else {
      this.tasks.push(task);        // 放到任务队列尾部
    }
  }

  eat(name) {
    const task = () => {
      console.log(`Eat ${name}`);
      this.next();
    }
    this.tasks.push(task);
    return this;
  }
}

function LazyMan(name) {
  return new _LazyMan(name);
}

posted @ 2020-05-07 11:03  Magi黄元  阅读(265)  评论(0编辑  收藏  举报