了解Maclean Liu|向Maclean Liu提问 Oracle ALLSTARS 全明星(群内有多位Oracle高级售后support,N位OCM和ACE) QQ群 # QQ群号:23549328 # 已经升级到 2000人群,空位多多。欢迎有一定基础的Oracle骨友加入,现在入群需要经过Maclean的技术面试,欢迎面试,请加QQ号:47079569 为好友参加面试 2群基础群 适合刚入门的同学,会共享最佳入门实践和资料 QQ群 # QQ群号:171092051 # 已经升级到 500人的超级群,空位多多,无需面试

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SQL> alter table emp add constraint emp_fk_dept foreign key(deptno) 2    references dept(deptno); Table altered. 试看代码演示9中的执行计划 代码演示9: SQL> select ename from emp_dept; Execution Plan ------------------------------ Plan hash value: 3956160932 -------------------------------------------------------------------------- | Id  | Operation         | Name | Rows  | Bytes | Cost (%CPU)| Time     | -------------------------------------------------------------------------- |   0 | SELECT STATEMENT  |      | 50000 |   976K| 27152   (1)| 00:05:26 | |*  1 |  TABLE ACCESS FULL| EMP  | 50000 |   976K| 27152   (1)| 00:05:26 | -------------------------------------------------------------------------- Predicate Information (identified by operation id): --------------------------------------------------- 1 - filter("EMP"."DEPTNO" IS NOT NULL) 如上dept表在以上查询中无需再在考虑之内了,故也谈不上哈希连接了,多出了一个断言:deptno是非空的。 优化器意识到外键和逐渐的存在,以上查询实际等效于 SELECT ENAME FROM EMP WHERE DEPTNO IS NOT NULL。 优化器舍弃了不必要的表,获得了响应时间上的进步。 同时也证明了实际应用中不因该总是使用SELECT *以简化应用的实施。 NULL对于索引的影响:

Indexes and NULLs

Applies to:

Oracle Server - Enterprise Edition - Version: 9.2.0.8 to 10.2.0.4 - Release: 9.2 to 10.2 Information in this document applies to any platform.

Purpose

This article illustrates some common reasons why indexes are not selected when NULLs are present.

Scope and Application

This is a basic level overview with examples of index usage.

Indexes and NULLs

Indexes and NULLs

When dealing with indexes, a common mistake is to forget about NULLs. Indexes do not store NULL values and so indexes on NULLable columns can't be used to drive queries unless there is something that eliminates the NULL values from the query. To illustrate this are a number of examples based upon the following table/indexes:
drop table nulltest; create table nulltest ( col1 number, col2 number, col3 number not null, col4 number not null); create index nullind1 on nulltest (col1); create index notnullind3 on nulltest (col3); begin for i in 1..10000 loop insert into nulltest values (i,i,i,i); if i mod 1000 = 0 then commit; end if; end loop; end; / analyze table nulltest compute statistics;

Illustrative Queries:

select col1 from nulltest t; select /*+ index(t nullind1) */ col1 from nulltest t; select /*+ index(t) */ col1 from nulltest t; select /*+ index(t notnullind3) */ col1 from nulltest t; select /*+ index(t notnullind3) */ col3 from nulltest t; select /*+ index(t nullind1) */ col1 from nulltest t where col1 between 0 and 20000; select col1 from nulltest t where col1 is not null;

Queries and Explanations:

SQL> select col1 from nulltest t; Execution Plan ---------------------------------------------------------- 0 SELECT STATEMENT Optimizer=CHOOSE (Cost=6 Card=10000 Bytes=30000) 1 0 TABLE ACCESS (FULL) OF 'NULLTEST' (Cost=6 Card=10000 Bytes=30000)
col1 is NULLable so the index cannot be used with no predicate
SQL> select /*+ index(t nullind1) */ col1 from nulltest t; Execution Plan ---------------------------------------------------------- 0 SELECT STATEMENT Optimizer=CHOOSE (Cost=6 Card=10000 Bytes=30000) 1 0 TABLE ACCESS (FULL) OF 'NULLTEST' (Cost=6 Card=10000 Bytes=30000)
hinting the index on col1 (nullind1) makes no difference since col1 is NULLable
SQL> select /*+ index(t) */ col1 from nulltest t; Execution Plan ---------------------------------------------------------- 0 SELECT STATEMENT Optimizer=CHOOSE (Cost=49 Card=10000 Bytes=30000) 1 0 TABLE ACCESS (BY INDEX ROWID) OF 'NULLTEST' (Cost=49 Card=10000 Bytes=30000) 2 1 INDEX (FULL SCAN) OF 'NOTNULLIND3' (NON-UNIQUE) (Cost=20 Card=10000)
An open index hint on the table allows the selection of the index on the NOT NULL column (col3). Notice that the col3 predicate is not included anywhere in the query. In order for col1 to be retrieved, the table has to be accessed.
SQL> select /*+ index(t notnullind3) */ col1 from nulltest t; Execution Plan ---------------------------------------------------------- 0 SELECT STATEMENT Optimizer=CHOOSE (Cost=49 Card=10000 Bytes=30000) 1 0 TABLE ACCESS (BY INDEX ROWID) OF 'NULLTEST' (Cost=49 Card=10000 Bytes=30000) 2 1 INDEX (FULL SCAN) OF 'NOTNULLIND3' (NON-UNIQUE) (Cost=20 Card=10000)
hinting notnullind3 directly works as well
SQL> select /*+ index(t notnullind3) */ col3 from nulltest t; Execution Plan ---------------------------------------------------------- 0 SELECT STATEMENT Optimizer=CHOOSE (Cost=20 Card=10000 Bytes=30000) 1 0 INDEX (FULL SCAN) OF 'NOTNULLIND3' (NON-UNIQUE) (Cost=20 Card=10000 Bytes=30000)
Selecting the NOT NULL column (col3) works fine and uses the index with no table access.
SQL> select /*+ index(t nullind1) */ col1 from nulltest t where col1 between 0 and 20000; Execution Plan ---------------------------------------------------------- 0 SELECT STATEMENT Optimizer=CHOOSE (Cost=20 Card=10000 Bytes=30000) 1 0 INDEX (RANGE SCAN) OF 'NULLIND1' (NON-UNIQUE) (Cost=20 Card=10000 Bytes=30000)
The effect of the predicate against col1 is to eliminate nulls from the data returned from the column. This allows the index to be used.
SQL> select col1 from nulltest t 2 where col1 is not null; Execution Plan ---------------------------------------------------------- 0 SELECT STATEMENT Optimizer=CHOOSE (Cost=5 Card=10000 Bytes=30000) 1 0 INDEX (FAST FULL SCAN) OF 'NULLIND1' (NON-UNIQUE) (Cost=5 Card=10000 Bytes=30000)
This example illustrates that forcing the column to return only NOT NULL values allows the index to be used. Note that in the previous example, the Index hint prevents an index fast full scan operation from being selected. An INDEX_FFS hint must be supplied to force an index fast full scan.

posted on 2009-08-17 11:44  Oracle和MySQL  阅读(252)  评论(0编辑  收藏  举报

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