Python第四次作业------李珠霞
2019-05-08 21:05 李珠霞 阅读(237) 评论(0) 编辑 收藏 举报设计题1:
设计一个本月份日历,输出格式如下:
要求:
1.初始化start_day,end_day两个日期
from datetime import datetime
start_day=datetime(2019,4,1)
end_day=datetime(2019,4,30)
其它时间数据生成要用datetime或date模块的方法编程实现
2.不能使用calendar模块生成
from datetime import datetime start_day=datetime(2019,4,1) end_day=datetime(2019,4,30) count = 0 print("\t\t\t2019年4月") print("星期一 星期二 星期三 星期四 星期五 星期六 星期天") for i in range (0,30): i=i+1 print(i,end="\t\t") count=count+1 if count%7==0: print("\n")
码云地址:https://gitee.com/Cream_k/lzx/commit/94ab94881503630f57f4f5dc2ae16771dbef28ec
设计题2:
1.参考“三国演义”词频统计程序,实现对红楼梦出场人物的频次统计。
2.(可选)
将红楼梦出场人物的频次统计结果用词云显示。
import jieba excludes = {"一个","一回","袭人","银子","王夫人","东西","姑娘","什么" ,"我们","贾母","那里","说道","众人","一面","这个","不知","没有","两个" ,"奶奶","怎么","只见","自己","他们","出来","这里","起来","知道","如今","你们", "一个","我们","那里","如今","说道","知道","起来","姑娘","这里","出来", "他们","众人","自己","一面","只见","太太","两个","没有","不是","不知", "这个","听见","这样","进来","咱们","告诉","怎么","就是","东西","回来","只是", "老爷","大家","只得","丫头","这些","不敢","出去","所以","的话","不好","姐姐"} txt = open(r"C:\Users\ASUS\PycharmProjects\untitled\红楼梦.txt", "r", encoding='utf-8').read() words = jieba.lcut(txt)#精确模式的分词函数,返回一个列表数据类型 #print(type(words)) #words的数据类型 counts = {} #定义一个字典 for word in words: if len(word) == 1: continue elif word == "宝玉" or word == "宝二爷" or word == "怡红公子" or word == "绛洞花主" or word == "无事忙" or word == "遮天大王" or word == "混世魔王" or word == "槛内人" or word == "浊玉": rword = "贾宝玉" elif word == "林黛玉" or word == "黛玉道": rword = "林黛玉" elif word == "宝钗" or word == "蘅芜君" or word == "宝姐姐" or word == "宝丫头" or word == "宝姑娘": rword = "薛宝钗" elif word == "凤姐" or word == "琏二奶奶" or word=="凤辣子"or word=="凤哥儿"or word=="凤丫头" or word=="凤姐儿" or word == "熙凤道": rword = "王熙凤" elif word == "贾母" or word == "老太太": rword = "贾母" elif word == "贾探春" or word == "探春": rword = "探春" elif word == "秦可卿" or word == "可卿": rword = "可卿" elif word == "司棋" or word == "司棋道": rword = "司棋" else: rword = word counts[rword] = counts.get(rword,0) + 1 #词汇加入字典 for word in excludes: del(counts[word]) #从字典中删除无用词 items = list(counts.items())#字典转换为列表 #lambda是一个隐函数,是固定写法,以下命令的意思就是按照记录的第2列排序 """x表示列表中的一个元素,x只是临时起的一个名字, 你可以使用任意的名字""" items.sort(key=lambda x:x[1], reverse=True) for i in range(7): #出现的词频统计 word, count = items[i] #将键和值分别赋予列表word和countf print ("{0:<10}{1:>5}".format(word, count))#0:<10左对齐,宽度10,”>5"右对齐
码云地址:https://gitee.com/Cream_k/lzx/commit/ff0298837991943fd15e6b997306545bac9336fa