摘要:
def he (n): if n < 3 : return 1 return he(n-1)+he(n-2)print(he(n)) 阅读全文
摘要:
def he (n): if n < 3 : return 1 return he(n-1)+he(n-2)print(he(n)) 阅读全文
摘要:
def chengji(n): if n == 0: return 1 return chengji(n-1)*nprint(chengji(n)) 阅读全文
|