hdu 1180

地址:http://acm.hdu.edu.cn/showproblem.php?pid=1180

题意:中文。

mark:题目没说明楼梯改变情况。sample中的路径应该是先向上走,再向右走,通过楼梯后走到头再向上,这里wa了1次。

bfs+优先队列。优先队列用手写堆实现。数据规模很小。

代码:

# include <stdio.h>
# include <string.h>


char graph[25][25] ;
int dr[4][2] = {0,1,0,-1,1,0,-1,0} ;
int sx, sy, ex, ey ;
int vis[25][25] ;
int q[25*25*10][3], qcnt ;
int n, m ;


void swap(int a[3], int b[3])
{
int i, t ;
for( i = 0 ; i < 3 ; i++)
t = a[i], a[i] = b[i], b[i] = t ;
}


void qpush(int x, int y, int t)
{
int idx = qcnt++ ;
q[idx][0] = x, q[idx][1] = y, q[idx][2] = t ;
while (idx != 1)
{
if (q[idx][2] < q[idx/2][2])
swap(q[idx], q[idx/2]) ;
else break ;
idx /= 2 ;
}
}


void heapify(int idx)
{
int l = idx*2, r=idx*2+1, least = idx ;
if (l<qcnt && q[l][2]<q[least][2])
least = l ;
if (r<qcnt && q[r][2]<q[least][2])
least = r ;
if (least == idx) return ;
swap(q[least], q[idx]) ;
heapify(least) ;
}


void qpop(int *px, int *py, int *pt)
{
*px = q[1][0], *py = q[1][1], *pt = q[1][2] ;
swap(q[1], q[--qcnt]) ;
heapify(1) ;
}


int bfs()
{
int i, front = 0, rear = 2 ;
int x, y, t, xx, yy ;
vis[sx][sy] = 1 ;
qpush(sx, sy, 0) ;
qpush(sx, sy, 1) ;
while (qcnt != 1)
{
qpop(&x, &y, &t) ;
printf ("%d %d %d\n", x, y, t) ;
if (x == ex && y == ey) return t ;
for(i = 0 ; i < n ;i++)
{
xx = x + dr[i][0], yy = y + dr[i][1] ;
if (xx < 0 || xx >= n) continue ;
if (yy < 0 || yy >= m) continue ;
//楼梯改变坐标
if (graph[xx][yy] == '-' || graph[xx][yy] == '|')
{
if (i>=2) //左右
{
if (((t%2 == 0) && (graph[xx][yy] == '|')) ||
((t%2 == 1) && (graph[xx][yy] == '-')))
{
xx += dr[i][0] ;
yy += dr[i][1] ;
}
else continue ;
}
else //上下
{
if (((t%2 == 0) && (graph[xx][yy] == '-')) ||
((t%2 == 1) && (graph[xx][yy] == '|')))
{
xx += dr[i][0] ;
yy += dr[i][1] ;
}
else continue ;
}
if (xx < 0 || xx >= n || yy < 0 || yy >= m) continue ;
}
if (graph[xx][yy] == '*') continue ;
if (vis[xx][yy]) continue ;
vis[xx][yy] = 1 ;
qpush(xx, yy, t+1) ;
qpush(xx, yy, t+2) ;
}
}
return -1 ;
}


int main ()
{
int i, j, ans ;
while (~scanf ("%d %d%*c", &n, &m))
{
for (i = 0 ; i <n ; i++)
scanf ("%s%*c", graph[i]) ;
for(i = 0 ; i < n ; i++)
for (j = 0 ; j < m ; j++)
{
if (graph[i][j] == 'S') sx = i, sy = j ;
else if (graph[i][j] == 'T') ex = i, ey = j ;
}
memset (vis, 0, sizeof(vis)) ;
qcnt = 1 ;
ans = bfs() ;
printf ("%d\n", ans) ;
}
return 0 ;
}



posted @ 2012-01-20 04:52  Seraph2012  阅读(279)  评论(0编辑  收藏  举报