实验六
任务四
源代码：
#include <stdio.h> #define N 10 typedef struct { char isbn[20]; char name[80]; char author[80]; double sales_price; int sales_count; } Book; void output(Book x[], int n); void sort(Book x[], int n); double sales_amount(Book x[], int n); int main() { Book x[N] = {{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51}, {"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30}, {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27}, {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90}, {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49}, {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42}, {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44}, {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42}, {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55}, {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}}; printf("图书销量排名(按销售册数): \n"); sort(x, N); output(x, N); printf("\n图书销售总额: %.2f\n", sales_amount(x, N)); return 0; } void output(Book x[], int n) { int i; printf("%-20s %-30s %-20s %-10s %-10s\n","ISBN号","书名", "作者", "售价", "销售册数"); for (i=0;i<n;i++) { printf("%-20s %-30s %-20s %-10.2f %-10d\n",x[i].isbn,x[i].name,x[i].author,x[i].sales_price,x[i].sales_count); } } void sort(Book x[], int n) { int i, j; for (i = 0; i < n - 1 ; i++) { for (j = 0; j < n - 1 - i; j++) { if (x[j].sales_count < x[j + 1].sales_count) { Book temp = x[j]; x[j] = x[j+1]; x[j+1] = temp; } } } } double sales_amount(Book x[], int n) { double sum = 0; int i; for (i = 0; i < n; i++) { sum += x[i].sales_price * x[i].sales_count; } return sum; }
运行结果：
任务五
源代码：
#include <stdio.h> typedef struct { int year; int month; int day; } Date; void input(Date *pd); int day_of_year(Date d); int compare_dates(Date d1, Date d2); void test1() { Date d; int i; printf("输入日期:(以形如2024-12-16这样的形式输入)\n"); for(i = 0; i < 3; ++i) { input(&d); printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d)); } } void test2() { Date Alice_birth, Bob_birth; int i; int ans; printf("输入Alice和Bob出生日期:(以形如2024-12-16这样的形式输入)\n"); for(i = 0; i < 3; ++i) { input(&Alice_birth); input(&Bob_birth); ans = compare_dates(Alice_birth, Bob_birth); if(ans == 0) printf("Alice和Bob一样大\n\n"); else if(ans == -1) printf("Alice比Bob大\n\n"); else printf("Alice比Bob小\n\n"); } } int main() { printf("测试1: 输入日期, 打印输出这是一年中第多少天\n"); test1(); printf("\n测试2: 两个人年龄大小关系\n"); test2(); } void input(Date *pd) { scanf("%d-%d-%d-", &(pd->year),&(pd->month),&(pd->day)); } int day_of_year(Date d) { int days_per_month[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; int days = d.day; int i; if ((d.year % 4 == 0 && d.year % 100 != 0) || (d.year % 400 == 0)) { days_per_month[2] = 29; } for (i = 1; i < d.month;i++) { days += days_per_month[i]; } return days; } int compare_dates(Date d1, Date d2) { int year1 = d1.year; int year2 = d2.year; int day1 = day_of_year(d1); int day2 = day_of_year(d2); if (year1 < year2) { return -1; } else if (year1 > year2) { return 1; } else if (day1 < day2) { return -1; } else if (day1 > day2) { return 1; } else { return 0; } }
运行结果：
任务六
源代码：
#include <stdio.h> #include <string.h> enum Role {admin, student, teacher}; typedef struct { char username[20]; char password[20]; enum Role type; } Account; void output(Account x[], int n); int main() { Account x[] = {{"A1001", "123456", student}, {"A1002", "123abcdef", student}, {"A1009", "xyz12121", student}, {"X1009", "9213071x", admin}, {"C11553", "129dfg32k", teacher}, {"X3005", "921kfmg917", student}}; int n; n = sizeof(x)/sizeof(Account); output(x, n); return 0; } void output(Account x[], int n) { int i, j; for (i = 0; i < n;i++) { printf("%-10s",x[i].username); for (j = 0; j < strlen(x[i].password);j++) { printf("*"); } printf("%-10s",""); if (x[i].type == admin) { printf("%-20s\n","admin"); } else if (x[i].type == student){ printf("%-20s\n","student"); } else if (x[i].type == teacher){ printf("%-20s\n","teacher"); } } }
运行结果：
任务七
源代码：
#include <stdio.h> #include <string.h> typedef struct { char name[20]; char phone[12]; int vip; } Contact; // 函数声明 void set_vip_contact(Contact x[], int n, char name[]); void output(Contact x[], int n); void display(Contact x[], int n); #define N 10 int main() { Contact list[N] = {{"刘一", "15510846604", 0}, {"陈二", "18038747351", 0}, {"张三", "18853253914", 0}, {"李四", "13230584477", 0}, {"王五", "15547571923", 0}, {"赵六", "18856659351", 0}, {"周七", "17705843215", 0}, {"孙八", "15552933732", 0}, {"吴九", "18077702405", 0}, {"郑十", "18820725036", 0}}; int vip_cnt, i; char name[20]; printf("显示原始通讯录信息: \n"); output(list, N); printf("\n输入要设置的紧急联系人个数: "); scanf("%d", &vip_cnt); printf("输入%d个紧急联系人姓名:\n", vip_cnt); for(i = 0; i < vip_cnt; ++i) { scanf("%s", name); set_vip_contact(list, N, name); } printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n"); display(list, N); return 0; } void set_vip_contact(Contact x[], int n, char name[]) { int i; for (i = 0;i < n;i++) { if (strcmp(x[i].name,name) == 0){ x[i].vip = 1; } } } void display(Contact x[], int n) { int i,j=0; Contact t; for(i=0;i<n-1;i++){ for(j=0;j<n-i-1;j++){ if(x[j].vip<x[j+1].vip){ t=x[j]; x[j]=x[j+1]; x[j+1]=t; } else if(x[j].vip==x[j+1].vip&&strcmp(x[j].name,x[j+1].name)>0){ t=x[j]; x[j]=x[j+1]; x[j+1]=t; } } } output(x,n); } void output(Contact x[], int n) { int i; for(i = 0; i < n; ++i) { printf("%-10s%-15s", x[i].name, x[i].phone); if(x[i].vip) printf("%5s", "*"); printf("\n"); } }
运行结果：
