js解析url参数返回json格式
urlQueryString:function(url){//scoreRecode.php?callback11=callajax11&callback=callajax
var url = url.split("?")[1];
var result = {},reg = /([^&=]+)=([^&]*)/g,m;
while(m = reg.exec(url)){
result[m[1]] = m[2];
}
return result;//Object {callback11: "callajax11", callback: "callajax"}
}
posted on 2013-04-26 10:56 liuyong1855 阅读(600) 评论(0) 编辑 收藏 举报