//连续的和的绝对值最小
# include <stdio.h>
# include <string.h>
# include <algorithm>
# include <math.h>
using namespace std;
int main()
{
int t,i,j,num,n,min1;
int sum[1010],a[1010];
int cas=0;
while(~scanf("%d",&t))
{
while(t--)
{
scanf("%d",&n);
for(i=0; i<n; i++)
scanf("%d",&a[i]);
min1=999999999;
for(i=0; i<n; i++)
{
sum[i]=abs(a[i]);
num=a[i];
for(j=i-1; j>=0; j--)
{
num=num+a[j];
if(sum[i]>abs(num))
sum[i]=abs(num);
}
if(min1>sum[i])
min1=sum[i];
}
printf("Case %d: %d\n",++cas,min1);
}
}
return 0;
}