数据库 批量查询结果作为更新的值

1. 数据库批量更新。

业务需求:

须要将a表中 type为1 的数据的source_id更新为新的id。

由于之前的id是存储在p_server中。如今更新到了server_info表中

update a set source_id = s.server_id  from 
(select p_server.p_id,p_server.index_code,server_info.server_id 
from p_server join server_info 
on p_server.index_code = server_info.index_code) s where 
a.source_id = s.p_id
and type = 1;

2. 更新数据库中的值。可是这些值存在不同的表中

CREATE OR REPLACE FUNCTION replace_img_url()
  RETURNS SETOF refcursor AS
$BODY$ 
DECLARE _ss_urls record;	
updateVehicle "varchar" := '';	
updateImage "varchar" := '';
ss_ip "varchar" := '';  
BEGIN          
for _ss_urls IN EXECUTE 'select svr_id as server_id,svr_ip||'':''||substring(svr_config,E''<httpPort>([0-9]*)?'') as url from server_multi_ip where svr_type = 20002'	loop 
   updateImage := 'update alarm_image set image_url = tep.url from (select alarm_event_id as event_id,time_happen,rule_id,sort_num, 
   replace(image_url, '''||_ss_urls.url||''','''||_ss_urls.server_id||''') as url from alarm_image) tep 
    where alarm_image.time_happen = tep.time_happen and alarm_image.alarm_event_id = tep.event_id and alarm_image.rule_id = tep.rule_id and alarm_image.sort_num = tep.sort_num';	   
  execute updateImage;	   

   updateVehicle :='update vehicle_recognition set vehicle_image_url = tep.url from (select vehicle_recog_id as id,vehicle_recog_id, replace(vehicle_image_url, '''||_ss_urls.url||''',
    '''||_ss_urls.server_id||''') as url from vehicle_recognition) tep where vehicle_recognition.vehicle_recog_id = tep.id';       
  execute updateVehicle;	    	
  end loop;   
 END;  $BODY$
  LANGUAGE plpgsql VOLATILE
  COST 100
  ROWS 1000;
ALTER FUNCTION replace_img_url() OWNER TO postgres;


posted @ 2017-07-03 18:08  lytwajue  阅读(988)  评论(0编辑  收藏  举报