Hint
For the first case, Soda can use 1 yuan to buy a set of 2 souvenirs.
For the second case, Soda can use 3 yuan to buy a souvenir.
#include<iostream>
#include<algorithm>
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<math.h>
using namespace std;
int main()
{
int T;
scanf("%d",&T);
while(T--)
{
__int64 sum = 0;
int n,m,p,q;
scanf("%d%d%d%d",&n,&m,&p,&q);
if(p*m<=q)
{
printf("%d\n",p*n);
}
else
{
sum = (n/m)*q;
n = n%m;
if(n*p<q)
{
printf("%I64d\n",sum+n*p);
}
else
{
printf("%I64d\n",sum+q);
}
}
}
return 0;
}