拦截器验证用户是否登录 (认证用户)代码实例

实现思路

1. 有一个登陆页面,需要写一个controller访问页面。

2. 登陆页面有一提交表单的动作。需要在controller中处理。判断用户名密码是否正确。如果正确, 向session中写入用户信息。返回登陆成功。

3. 拦截用户请求,判断用户是否登陆。如果用户已经登陆。放行, 如果用户未登陆,跳转到登陆页面

 

 

1. 编写一个登陆页面 login.jsp

<%@ page contentType="text/html;charset=UTF-8" language="java" %>
<html>
<head>
<title>Title</title>
</head>
<h1>登录页面</h1>
<hr>
<body>
<form action="${pageContext.request.contextPath}/user/login">
用户名:<input type="text" name="username"> <br>
密码: <input type="password" name="pwd"> <br>
<input type="submit" value="提交">
</form>
</body>
</html>

2. 编写一个Controller处理请求

package com.kuang.controller;
        import org.springframework.stereotype.Controller;
        import org.springframework.web.bind.annotation.RequestMapping;
        import javax.servlet.http.HttpSession;
@Controller
@RequestMapping("/user")
public class UserController {
    //跳转到登陆页面
    @RequestMapping("/jumplogin")
    public String jumpLogin() throws Exception {
        return "login";
    }
    //跳转到成功页面
    @RequestMapping("/jumpSuccess")
    public String jumpSuccess() throws Exception {
        return "success";
    }
    //登陆提交
    @RequestMapping("/login")
    public String login(HttpSession session, String username, String
            pwd) throws Exception {
// 向session记录用户身份信息
        System.out.println("接收前端==="+username);
        session.setAttribute("user", username);
        return "success";
    }
    //退出登陆
    @RequestMapping("logout")
    public String logout(HttpSession session) throws Exception {
// session 过期
        session.invalidate();
        return "login";
    }
}

3. 编写一个登陆成功的页面 success.jsp

<%@ page contentType="text/html;charset=UTF-8" language="java" %>
<html>
<head>
<title>Title</title>
</head>
<body>
<h1>登录成功页面</h1>
<hr>
${user}
<a href="${pageContext.request.contextPath}/user/logout">注销</a>
</body>
</html>

4. 在 index 页面上测试跳转!启动Tomcat 测试,未登录也可以进入主页!

<%@ page contentType="text/html;charset=UTF-8" language="java" %>
<html>
<head>
<title>$Title$</title>
</head>
<body>
<h1>首页</h1>
<hr>
<%--登录--%>
<a href="${pageContext.request.contextPath}/user/jumplogin">登录</a>
<a href="${pageContext.request.contextPath}/user/jumpSuccess">成功页面
</a>
</body>
</html>

5. 编写用户登录拦截器

package com.kuang.interceptor;
        import org.springframework.web.servlet.HandlerInterceptor;
        import org.springframework.web.servlet.ModelAndView;
        import javax.servlet.ServletException;
        import javax.servlet.http.HttpServletRequest;
        import javax.servlet.http.HttpServletResponse;
        import javax.servlet.http.HttpSession;
        import java.io.IOException;
public class LoginInterceptor implements HandlerInterceptor {
    public boolean preHandle(HttpServletRequest request,
                             HttpServletResponse response, Object handler) throws ServletException,
            IOException {
// 如果是登陆页面则放行
        System.out.println("uri: " + request.getRequestURI());
        if (request.getRequestURI().contains("login")) {
            return true;
        }
        HttpSession session = request.getSession();
// 如果用户已登陆也放行
        if(session.getAttribute("user") != null) {
            return true;
        }
// 用户没有登陆跳转到登陆页面
        request.getRequestDispatcher("/WEBINF/jsp/login.jsp").forward(request, response);
        return false;
    }
    public void postHandle(HttpServletRequest httpServletRequest,
                           HttpServletResponse httpServletResponse, Object o, ModelAndView
                                   modelAndView) throws Exception {
    }
    public void afterCompletion(HttpServletRequest httpServletRequest,
                                HttpServletResponse httpServletResponse, Object o, Exception e) throws
            Exception {
    }
}

6. 在Springmvc的配置文件中注册拦截器

       <!--关于拦截器的配置-->
<mvc:interceptors>
<mvc:interceptor>
    <mvc:mapping path="/**"/>
    <bean id="loginInterceptor"
          class="com.kuang.interceptor.LoginInterceptor"/>
</mvc:interceptor>
</mvc:interceptors>

7. 再次重启Tomcat测试!

OK,测试登录拦截功能无误.

 

 

 
posted @ 2022-02-25 23:55  临易  阅读(148)  评论(0编辑  收藏  举报