编程菜鸟的日记-初学尝试编程-单链表
//单链表的头插法和尾插法建立，以及直接插入法递增排序
#include <iostream>
#include <string>
#include <stdlib.h>
#define ElemType int
using namespace std;
typedef struct List
{
ElemType data;
struct List *next;
}List;
void CreatListF(List *L,ElemType a[],int n)
{
List *s;
L->next=NULL;
int i;
for(i=0;i<n;i++)
{
s=(List *)malloc(sizeof(struct List));
s->data=a[i];
s->next=L->next;
L->next=s;
}
}
void CreatListR(List *L, ElemType a[],int n)
{
List *r,*s;
L->next=NULL;
r=L;
int i;
for(i=0;i<n;i++)
{
s=(List *)malloc(sizeof(struct List));
s->data=a[i];
r->next=s;
r=s;
}
r->next=NULL;
}
void SortList(List *L)
{
List *p=L->next,*q,*r;
if(p!=NULL)
{
r=p->next;
p->next=NULL;
p=r;
while(p!=NULL)
{
r=p->next;
q=L;
while(q->next!=NULL && q->next->data<p->data)
{
q=q->next;
}
p->next=q->next;
q->next=p;
p=r;
}
}
}
void Display(List *L)
{
List *p=L->next;
while(p!=NULL)
{
cout<<p->data<<" ";
p=p->next;
}
cout<<endl;
}
int main()
{
List *L1,*L2;
L1=(List *)malloc(sizeof(struct List));
L2=(List *)malloc(sizeof(struct List));
ElemType a[10]={7,6,1,4,9,10,5,8,2,3};
int n=sizeof(a)/sizeof(ElemType);
CreatListF(L1,a,n);
Display(L1);
CreatListR(L2,a,n);
Display(L2);
SortList(L1);
Display(L1);
SortList(L2);
Display(L2);
system("pause");
return 0;
}
