MYSQL练习题(45题)
建表语句
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 | -- 学生表 Student create table Student(SId varchar (10),Sname varchar (10),Sage datetime,Ssex varchar (10)); insert into Student values ( '01' , '赵雷' , '1990-01-01' , '男' ); insert into Student values ( '02' , '钱电' , '1990-12-21' , '男' ); insert into Student values ( '03' , '孙风' , '1990-05-20' , '男' ); insert into Student values ( '04' , '李云' , '1990-08-06' , '男' ); insert into Student values ( '05' , '周梅' , '1991-12-01' , '女' ); insert into Student values ( '06' , '吴兰' , '1992-03-01' , '女' ); insert into Student values ( '07' , '郑竹' , '1989-07-01' , '女' ); insert into Student values ( '09' , '张三' , '2017-12-20' , '女' ); insert into Student values ( '10' , '李四' , '2017-12-25' , '女' ); insert into Student values ( '11' , '李四' , '2017-12-30' , '女' ); insert into Student values ( '12' , '赵六' , '2017-01-01' , '女' ); insert into Student values ( '13' , '孙七' , '2018-01-01' , '女' ); 科目表 Course create table Course(CId varchar (10),Cname nvarchar(10),TId varchar (10)); insert into Course values ( '01' , '语文' , '02' ); insert into Course values ( '02' , '数学' , '01' ); insert into Course values ( '03' , '英语' , '03' ); 教师表 Teacher create table Teacher(TId varchar (10),Tname varchar (10)); insert into Teacher values ( '01' , '张三' ); insert into Teacher values ( '02' , '李四' ); insert into Teacher values ( '03' , '王五' ); 成绩表 SC create table SC(SId varchar (10),CId varchar (10),score decimal (18,1)); insert into SC values ( '01' , '01' , 80); insert into SC values ( '01' , '02' , 90); insert into SC values ( '01' , '03' , 99); insert into SC values ( '02' , '01' , 70); insert into SC values ( '02' , '02' , 60); insert into SC values ( '02' , '03' , 80); insert into SC values ( '03' , '01' , 80); insert into SC values ( '03' , '02' , 80); insert into SC values ( '03' , '03' , 80); insert into SC values ( '04' , '01' , 50); insert into SC values ( '04' , '02' , 30); insert into SC values ( '04' , '03' , 20); insert into SC values ( '05' , '01' , 76); insert into SC values ( '05' , '02' , 87); insert into SC values ( '06' , '01' , 31); insert into SC values ( '06' , '03' , 34); insert into SC values ( '07' , '02' , 89); insert into SC values ( '07' , '03' , 98); |
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 | 1.查询 " 01 " 课程比 " 02 " 课程成绩高的学生的信息及课程分数 SELECT a.* ,b.score 01课程成绩,c.score 02课程成绩 from student a ,sc b ,sc c where a.sid=b.sid and a.sid=c.sid and b.cid= '01' and c.cid= '02' and b.score>c.score 2.查询学过「张三」老师授课的同学的信息 SELECT a.* FROM student a JOIN sc b on a.sid=b.sid where b.cid in ( SELECT cid from course where cid in ( SELECT tid from teacher where Tname= '张三' )) 3.查询和 " 01 " 号的同学学习的课程 完全相同的其他同学的信息 -- 参考网友代码 SELECT s.* FROM student s LEFT JOIN ( SELECT sid,GROUP_CONCAT(cid) gc FROM sc GROUP BY sid) gs ON s.sid = gs.sid WHERE gs.gc = ( SELECT GROUP_CONCAT(cid) FROM sc WHERE sid =01) AND s.sid != 01;<br> |
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 | 5.查询各科成绩最高分、最低分和平均分 SELECT b.cname, max (score), min (score), avg (score) from sc a LEFT JOIN course b on a.cid=b.cid GROUP BY a.cid,b.cname 6.查询各学生的总成绩,按总成绩降序排列 SELECT sid , sum (score) as 总成绩 from sc GROUP BY sid ORDER BY 总成绩 desc 7.查询每门课程被选修的学生数 select a.CId,b.cname, count (a.cid) from sc a LEFT JOIN course b on a.cid=b.cid GROUP BY a.cid,b.cname; 8.查询课程名称为「数学」,且分数低于 60 的学生姓名和分数 SELECT b.sname,a.score from sc a JOIN student b on a.sid=b.sid where cid in ( SELECT cid from course WHERE cname= '数学' ) and a.score<60 9.查询有不及格数据的课程名称 SELECT a.*,b.cname from sc a left JOIN course b on a.cid=b.cid where a.score<60 10.求每门课程选修的的学生人数 select a.CId,b.cname, count (a.cid) from sc a LEFT JOIN course b on a.cid=b.cid GROUP BY a.cid,b.cname; 11.成绩不重复,查询选修「张三」老师所授课程的学生中,成绩最高的学生信息及其成绩 SELECT a.*,b.score from student a left join sc b on a.sid=b.sid where b.cid in ( SELECT cid from course c,teacher d where c.tid=d.tid and d.tname= '张三' ) and b.score in ( select DISTINCT MAX (score) from sc where cid in ( SELECT cid FROM course e LEFT JOIN teacher f on e.tid=f.tid where f.tname= '张三' )) 12.成绩有重复的情况下,查询选修「张三」老师所授课程的学生中,成绩最高的学生信息及其成绩 SELECT a.*,b.score from student a left join sc b on a.sid=b.sid where b.cid in ( SELECT cid from course c,teacher d where c.tid=d.tid and d.tname= '张三' ) and b.score in ( select MAX (score) from sc where cid in ( SELECT cid FROM course e LEFT JOIN teacher f on e.tid=f.tid where f.tname= '张三' )) 13.查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩 SELECT DISTINCT a.* from sc a,sc b where a.cid!=b.cid and a.score = b.score 14.检索至少选修两门课程的学生学号 SELECT sid , count (*) c FROM sc GROUP BY sc.sId HAVING c >=2 15.查询选修了全部课程的学生信息 SELECT * from student WHERE sid in ( SELECT sid from sc GROUP BY sid HAVING count (*) =( SELECT count (*) from course )) 16.按照出生日期来算,当前月日 < 出生年月的月日则,年龄减一 SELECT MONTH (NOW()) from student SELECT year (now())- year (Sage)-1 年龄减一,student.* from student where MONTH (NOW())- month (sage)<0 and day (NOW())- day (sage)<0 SELECT year (now())- year (Sage) 年龄减一,student.* from student where 17.查询本周过生日的学生 SELECT * from student where WEEK(DATE_FORMAT(now(), '%y%M%d' ))=WEEK(sage) 18.查询下周过生日的学生 SELECT * from student where week(DATE_FORMAT(NOW(), '%y%m%d' ))+1 =WEEK(sage); 19.查询教师所教课程且选修人数多于5人的教师姓名 SELECT a.tname from teacher a where tid in ( SELECT tid from course where cid in ( SELECT cid from sc GROUP BY cid having count (*)>5)) 20 查询选修“语文”课程的男同学的成绩 SELECT a.score,b.sname from sc a LEFT JOIN student b on a.sid =b.sid where b.ssex= '男' and cid in ( SELECT cid from course where cname= '语文' ) |
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 | 1.查询平均成绩大于等于 60 分的同学的学生编号和学生姓名和平均成绩 select b.SId,b.Sname, AVG (a.score) avgscore from student b left join sc a on b.SId = a.SId GROUP BY b.SId,b.Sname HAVING avgscore >=60 2.查询在 SC 表存在成绩的学生信息 select * from student where sid in ( select sid from sc) 3.查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩(没成绩的显示为 null ) select a.SId,a.Sname, count (b.CId) 选课总数, sum (b.score) 课程的总成绩 from student a left join sc b on a.SId=b.SId GROUP BY a.SId,a.Sname; 4.查询「李」姓老师的数量 SELECT count (*) 李姓老师的数量 from teacher where Tname like '李%' 5.查询没有学全所有课程的同学的信息 select * from student join ( select count (cid) 选修课程数,sid from sc group by sid HAVING count (cid)<( select count (cid) from course)) t where student.SId=t.sid union select s.*, 0 选修课程数,sid from student s where sid not in ( SELECT sid from sc); 6.查询至少有一门课与学号为 " 01 " 的同学所学相同的同学的信息 SELECT * from student s where s.SId in ( SELECT sc.SId from sc WHERE sc.CId in ( SELECT sc2.CId from sc sc2 where sc2.SId= '01' ) ) 7.查询没学过 "张三" 老师讲授的任一门课程的学生姓名 select * from student c where c.SId not in ( select a.SId from student a join sc b on a.SId=b.SId where b.CId in ( select a.CId from course a join teacher b on a.TId = b.TId where Tname = '张三' )); 8.查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩 select * from ( select avg (score) 平均成绩,sid from sc group by sid ) t1 , ( select count (*) 不及格课程数,sid from sc where score< 60 group by sid HAVING count (*)>=2) t2 where t1.sid=t2.sid 9.检索 " 01 " 课程分数小于 60,按分数降序排列的学生信息 select * from student join ( select * from sc where score<60 and cid= '01' order by score desc ) t on student.sid=t.sid; 10.按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩 select * from student s left join ( select sc.sid,sc.cid,sc.score, 平均成绩 from sc join ( select avg (score) 平均成绩,sid from sc group by sid ) t on sc.SId= t.sid order by 平均成绩 desc ) t2 on s.sid=t2.sid 11.统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[60-0] 及所占百分比 select total, CONCAT(s1/total*100, "%" ) '0-59 占比' , CONCAT(s2/total*100, "%" ) '60-70 占比' , CONCAT(s3/total*100, "%" ) '71-85 占比' , CONCAT(s4/total*100, "%" ) '86-100 占比' from course c1, ( select * from ( select count (*) total ,CId from sc group by cid) t0 left join ( select count (*) 's1' ,CId c1 from sc where sc.score BETWEEN 0 and 59 group by cid ) t1 on t0.cid=t1.c1 left join ( select count (*) 's2' ,CId c2 from sc where sc.score BETWEEN 60 and 70 group by cid ) t2 on t0.cid=t2.c2 left join ( select count (*) 's3' ,CId c3 from sc where sc.score BETWEEN 71 and 85 group by cid ) t3 on t0.cid=t3.c3 left join ( select count (*) 's4' ,CId c4 from sc where sc.score BETWEEN 86 and 100 group by cid ) t4 on t0.cid=t4.c4 ) ts where c1.CId=ts.cid 12.查询各科成绩前三名的记录 select * from student join ( select sc.sid,sc.score,sc.cid from sc join ( select max (score) maxscore ,cid from sc GROUP BY cid ) t where sc.CId=t.cid and sc.score=t.maxscore) t2 on student.sid=t2.sid 13.查询出只选修两门课程的学生学号和姓名 SELECT SId,Sname from student where SId in ( SELECT SId from sc GROUP BY SId HAVING COUNT (CId)=2); 14.查询男生、女生人数 SELECT Ssex, count (Ssex) from student GROUP BY Ssex 15.查询名字中含有「风」字的学生信息 SELECT * from student where Sname like '%风%' ; 16.查询同名同性学生名单,并统计同名人数 SELECT s1.Sname, count (*) 同名人数 from student s1 JOIN student s2 on s1.SId != s2.SId and s1.Sname=s2.Sname and s1.Ssex=s2.Ssex GROUP BY s1.Sname; 17.查询 1990 年出生的学生名单 SELECT * from student where Sage like '1990%' ; 18.查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列 SELECT CId, avg (score) avgscore from sc GROUP BY CId order by avgscore desc , CId asc 19.查询平均成绩大于等于 85 的所有学生的学号、姓名和平均成绩 SELECT sc.SId ,s.Sname, avg (score) avgscore from sc LEFT JOIN student s on sc.SId=s.SId GROUP BY sc.SId,s.Sname having avgscore>=85; 20.查询各学生的年龄,只按年份来算 SELECT year (now())- year (Sage),stu .* from student 21.查询所有学生的课程及分数情况(存在学生没成绩,没选课的情况也要罗列出来) SELECT * from student LEFT JOIN sc on stuednt.SId=sc.SId; 22.查询任何一门课程成绩在 70 分以上的姓名、课程名称和分数 SELECT s.Sname, c.Cname,sc.score FROM course c LEFT JOIN sc on c.CId=sc.CId LEFT JOIN student s on s.SId=sc.SId where sc.score>=70; 23.查询课程编号为 01 且课程成绩在 80 分以上的学生的学号和姓名 select * from student join ( select sid,score from sc where score>80 and cid= '01' ) t on student.SId= t.sid 24.查询每门功成绩最好的前两名 SELECT sc.* from sc ,( select a.sid,a.cid from sc as a left join sc as b on a.cid = b.cid and a.score<b.score group by a.cid, a.sid having count (b.CId)<2) t where sc.sid=t.sid and sc.cid=t.cid order by sc.cid; 25.统计每门课程的学生选修人数(超过 5 人的课程才统计)。 select CId, count (*) as countS from sc GROUP BY CId HAVING countS>5 ORDER BY countS,CId ASC |
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