软工第一次作业——小学四则运算

题目描述:

从《构建之法》第一章的 “程序” 例子出发,像阿超那样,花二十分钟写一个能自动生成小学四则运算题目的命令行 “软件”,满足以下需求:

    1. 除了整数以外,还要支持真分数的四则运算,真分数的运算,例如:1/6 + 1/8 = 7/24
    2. 运算符为 +, −, ×, ÷
    3. 并且要求能处理用户的输入,并判断对错,打分统计正确率。
    4. 要求能处理用户输入的真分数, 如 1/2, 5/12 等
    5. 使用 -n 参数控制生成题目的个数,例如执行下面命令将生成10个题目
      Myapp.exe -n 10

需求分析:

  1. 能够实现生成整数和分数的式子并实现计算;
  2. 能够控制生成式子的个数;
  3. 能够实现判断对错并计算正确率;

设计实现:

  1. 通过if实现选择生成整数或分数的式子并计算;
  2. 显示正确率

代码说明:

#pragma warning(disable:4996)
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#include<windows.h>
#include<string.h>


using namespace std;

#define OPERATOR 4


//获取随机运算符
char getopre() {
    char oper[OPERATOR] = { '+','-','*','/' };
    srand((unsigned)time(NULL));
    return oper[rand() % 4];
}
//获取随机数
int random(double start, double end)

{
    return (int)(start + (end - start)*rand() / (RAND_MAX + 1.0));
}



//列式子
void equation() {
    int num1;
    int num2;
    int result;
    int answer;
    char oper;
    int right=0;
    float accuracy;
    int i, n;
    printf("请输入要生成的式子数:");
    scanf("%d", &n);
    for (i = 0; i < n; i++) {
        srand((unsigned)time(NULL));
        oper = getopre();
        num1 = random(0, 20);
        num2 = random(1, 20);
        switch (oper)
        {
        case '+':  result = num1 + num2;
            printf("%d+%d=\n", num1, num2); break;
        case '-':  result = num1 - num2;
            printf("%d-%d=\n", num1, num2); break;
        case '*':  result = num1*num2;
            printf("%d*%d=\n", num1, num2); break;
        case '/':  num1 = num1*num2;
                   result = num1 / num2; 
                   printf("%d÷%d=\n", num1, num2);
                   break;
        }
        //printf("%d%c%d=\n", num1, oper, num2);
        printf("请输入你的答案:");
        scanf("%d", &answer);
        if (result==answer) {
            printf("恭喜你答对了\n\n");
            right++;
        }
        else {
            printf("对不起答错了\n");
            printf("正确答案为:%d\n\n", result);
        }
    }
    accuracy = ((float)right /(float) n)*100;
    printf("正确率为百分之%1.2f\n", accuracy);
}

//真分数列式

void fraction() {
    
    int num1;
    int num2;
    int num3;
    int num4;
    int a, b;
    int answer1, answer2;
    float result;
    float answer;
    char oper;
    int right = 0;
    float accuracy;
    int i, n;
    printf("请输入要生成的式子数:");
    scanf("%d", &n);
    for (i = 0; i < n; i++) {
        srand((unsigned)time(NULL));
        oper = getopre();
        num1 = random(0, 20);
        num2 = random(1, 20);
        num3 = random(0, 20);
        num4 = random(1, 20);
        switch (oper)
        {
        case '+': 
            a = num1*num4+num3*num2;
            b = num2*num4;
            result = (float)a / (float)b;
            printf("%d/%d+%d/%d=\n", num1, num2, num3, num4); break;
        case '-': 
            a = num1*num4 - num3*num2;
            b = num2*num4;
            result = (float)a / (float)b;
            printf("%d/%d-%d/%d=\n", num1, num2, num3, num4); break;
        case '*':  
            a = num1*num3;
            b = num2*num4;
            result = (float)a / (float)b;
            printf("%d/%d*%d/%d=\n", num1, num2,num3, num4); break;
        case '/': 
            a = num1*num4;
            b = num2*num3;
            result =(float) a /(float) b;
            printf("%d/%d÷%d/%d=\n", num1, num2, num3, num4);
            break;
        }
        printf("请输入你的答案:\n");
        scanf("%d", &answer1);
        printf("/\n");
        scanf("%d", &answer2);
        answer = (float)answer1 / (float)answer2;
        if (result==answer) {
            printf("恭喜你答对了\n\n");
            right++;
        }
        else {
            printf("对不起答错了\n");
            printf("正确答案为:%d/%d\n\n", a,b);
        }
    }
    accuracy = ((float)right / (float)n) * 100;
    printf("正确率为百分之%1.2f\n", accuracy);
}


//主函数

void main() {
    int choose;
    printf("输入1生成整数算式,其他生成分式算式:");
    scanf("%d", &choose);
    if (choose == 1) {
        equation();
    }
    else {
        fraction();
    }
}

测试运行:

PSP展示:

PSP2.1 Personal Software Process Stages Time (%) Senior Student(/hour) Time (%)(/hour)
· Planning 计划 2 2
· Estimate 估计这个任务需要多少时间 30 31
· Analysis 需求分析 (包括学习新技术) 1 1
· Coding Standard 代码规范 0.5 0.5
· Design 具体设计 2 1
· Coding 具体编码 25 27
· Test 测试(自我测试,修改代码,提交修改) 1 1
Reporting 报告 1 1

码云链接:https://git.coding.net/ras/work1.git

 

posted on 2017-03-06 15:02  ras  阅读(139)  评论(1编辑  收藏  举报