第八次作业
1、编写一个简单程序,要求数组长度为5,分别赋值10,20,30,40,50,在控制台输出该数组的值
package bbb; public class Test1 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub int []a=new int[5]; a[0]=10; for (int i = 1; i < a.length; i++) { a[i]=a[i-1]+10; } for (int j : a) { System.out.println(j); } } }
2、将一个字符数组的值(neusofteducation)拷贝到另一个字符数组中
package bbb; import java.util.Arrays; public class Test2 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub String []a={"neusofteducation"}; String []b=new String[a.length]; for (int i = 0; i < b.length; i++) { b[i]=a[i]; } System.out.println(Arrays.toString(b)); } }
3、给定一个有9个整数(1,6,2,3,9,4,5,7,8)的数组,先排序,然后输出排序后的数组的值
package bbb; public class Test3 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub int []a={1,6,2,3,9,4,5,7,8}; for (int i = 0; i < a.length-1; i++) { for (int j = 0; j < a.length-1-i; j++) { if(a[j]>a[j+1]){ int temp=a[j]; a[j]=a[j+1]; a[j+1]=temp; } } } for (int i : a) { System.out.println(i); } } }
4、 输出一个double型二维数组(长度分别为5、4,值自己设定)的值
package bbb; public class Test4 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub double [][]a=new double[5][4]; for (int i = 0; i < a.length; i++) { for (int j = 0; j < a[i].length; j++) { a[i][j]=j; } } System.out.println("矩阵是"); for (int i = 0; i < a.length; i++) { for (int j = 0; j < a[i].length; j++) { System.out.print(a[i][j]+" "); } System.out.println(); } } }
5、 在一个有8个整数(18,25,7,36,13,2,89,63)的数组中找出其中最大的数及其下标
package bbb; public class Test5 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub int []a={18,25,7,36,13,2,89,63}; int max=a[0]; int maxidx=0; for (int i = 0; i < a.length; i++) { if(a[i]>max){ max=a[i]; maxidx=i; } } System.out.println("最大值是"+max+"它的下标是"+maxidx); } }
6、将一个数组中的元素逆序存放(知识点:数组遍历、数组元素访问)
package bbb; public class Test6 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub int a[] =new int[10]; for (int i = 0; i < a.length; i++) { a[i] =i; } for (int i : a) { System.out.print(i +" "); } System.out.println(); for (int i = 0; i < a.length; i++) { for (int j = i; j < a.length; j++) { int temp =a[i]; a[i] =a[j]; a[j] =temp; } } for (int i : a) { System.out.print(i +" "); } } }
8、给定一维数组{ -10,2,3,246,-100,0,5},计算出数组中的平均值、最大值、最小值。(知识点:数组遍历、数组元素访问)
package bbb; public class Test8 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub int a[] = { -10, 2, 3, 246, -100, 0, 5 }; int max = a[0]; int min = a[0]; double sum = 0; for (int i = 1; i < a.length; i++) { if (a[i] > max) { max = a[i]; } if (a[i] < min) { min = a[i]; } } for (int i = 0; i < a.length; i++) { sum += a[i]; } System.out.println("最大值为:" + max); System.out.println("最小值为:" + min); System.out.println("平均值为:" + sum / a.length); } }
9、使用数组存放裴波那契数列的前20项 ,并输出 1 1 2 3 5 8 13 21
package bbb; public Test9{ /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub int a[] = new int[20]; a[0] = 1; a[1] = 1; for (int i = 2; i < a.length; i++) { a[i] = a[i - 1] + a[i - 2]; } for (int i = 0; i < 8; i++) { System.out.println(a[i]); } } }
10、生成一个长度为10的随机整数数组(每个数都是0-100之间),输出,排序后,再输出
package bbb; import java.util.Arrays; import java.util.Random; public Test10 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub int []a=new int[10]; Random x=new Random(); for(int i=0;i<10;i++) { a[i]=x.nextInt(101); } System.out.println("输出为"); for(int h:a) {System.out.print(" "+h);} System.out.println(); System.out.println("排序后输出为"); int m=a[0]; Arrays.sort(a); for(int h:a) {System.out.print(" "+h);} } }