POJ 2686 打印完数

时间限制: 
1000ms
内存限制: 
65536kB
描述
一个数如果恰好等于它的因子之和,这个数就成为“完数”。例如,6的因子为1、2、3,而6=1+2+3,因此6是“完数”。编程序打印出1000之内(包括1000)所有的完数,并按如下格式输出其所有因子:

6 its factors are 1,2,3
输入
无输入
输出
输出1000以内所有的完数及其因子,每行一个完数。
样例输入

样例输出
(1)、源代码:
#include <iostream>
 
using namespace std;
 
int main()
{
                int yin[100];
                int sum, k, i, j, m;
                for(i = 6; i <= 1000; i++)
                {
                                sum = k = 0;
                                for(j = 1; j < i; j++){
                                                if(i % j == 0){
                                                                sum += j;
                                                                yin[k++] = j;
                                                }
                                }
                                if(i == sum){
                                                cout << i << " its factors are ";
                                                for(m = 0; m < k; m++){
                                                                cout << yin[m];
                                                                if(m != k - 1)
                                                                                cout << ",";
                                                }
                                                cout << endl;
                                }              
                }
                return 0;
}
 
(2)、解题思路:略
(3)、可能出错:略
 
 
 
 
posted on 2012-05-02 22:15  谷堆旁边  阅读(597)  评论(0编辑  收藏  举报