Given an n-ary tree, return the level order traversal of its nodes' values.
Nary-Tree input serialization is represented in their level order traversal, each group of children is separated by the null value (See examples).
Example 1:
Input: root = [1,null,3,2,4,null,5,6] Output: [[1],[3,2,4],[5,6]]
Example 2:
Input: root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14] Output: [[1],[2,3,4,5],[6,7,8,9,10],[11,12,13],[14]]
Constraints:
- The height of the n-ary tree is less than or equal to
1000
- The total number of nodes is between
[0, 10^4]
class Solution { public: vector<vector<int>> levelOrder(Node* root) { vector<vector<int>> res; vector<Node*> node,tmp; if(root)node.push_back(root); while(!node.empty()) { vector<int> row; for(Node *p:node) { row.push_back(p->val); for(Node *c:p->children) { if(c) tmp.push_back(c); } } res.push_back(row); node=tmp; tmp.clear(); } return res; } };