Given an array of strings, group anagrams together.

Example:

Input: ["eat", "tea", "tan", "ate", "nat", "bat"],
Output:
[
  ["ate","eat","tea"],
  ["nat","tan"],
  ["bat"]
]

Note:

  • All inputs will be in lowercase.
  • The order of your output does not matter.

 

基本的遍历练手题.

最开始试图用异或来做, 因为只要字母一样,不管顺序是什么 异或值是一样的..结果忘记了一个事情即使 异或值一样不能代表这俩string是一样的字母组成.

 

class Solution {
public:
    vector<vector<string>> groupAnagrams(vector<string>& strs) {
        unordered_map<string,vector<string>> res;
        for(int i=0;i<strs.size();++i)
        {
            string s= strs[i];
            sort(s.begin(),s.end());
            res[s].push_back(strs[i]);
        }
        
        vector<vector<string>> r;
        for(auto i=res.begin();i!=res.end();++i)
        {
            r.push_back(i->second);
        }
        return r;
    }
};