$\bf(Riesz引理)$设$X_0$为赋范线性空间$X$上的闭真子空间,则对任意的$\varepsilon > 0$,存在${x_0} \in X,\left\| {{x_0}} \right\| = 1$,使得对任意的$x \in {X_0}$,有\[\left\| {x - {x_0}} \right\| > 1 - \varepsilon \]
方法一 方法二
$\bf(Riesz引理)$
posted on 2014-06-26 15:50 285714 阅读(787) 评论(0) 编辑 收藏 举报
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