js根据经纬度计算两点距离
js版-胡老师
google.maps.LatLng.prototype.distanceFrom = function(latlng) {
var lat = [this.lat(), latlng.lat()]
var lng = [this.lng(), latlng.lng()]
var R = 6378137;
var dLat = (lat[1] - lat[0]) * Math.PI / 180;
var dLng = (lng[1] - lng[0]) * Math.PI / 180;
var a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.cos(lat[0] * Math.PI / 180) * Math.cos(lat[1] * Math.PI / 180) * Math.sin(dLng / 2) * Math.sin(dLng / 2);
var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1 - a));
var d = R * c;
return Math.round(d);
}
var lat = [this.lat(), latlng.lat()]
var lng = [this.lng(), latlng.lng()]
var R = 6378137;
var dLat = (lat[1] - lat[0]) * Math.PI / 180;
var dLng = (lng[1] - lng[0]) * Math.PI / 180;
var a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.cos(lat[0] * Math.PI / 180) * Math.cos(lat[1] * Math.PI / 180) * Math.sin(dLng / 2) * Math.sin(dLng / 2);
var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1 - a));
var d = R * c;
return Math.round(d);
}
一、经纬度算两点距离-百度api-精确度第一
<!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <meta name="viewport" content="initial-scale=1.0, user-scalable=no" /> <style type="text/css"> body, html,#allmap {width: 100%;height: 100%;overflow: hidden;margin:0;font-family:"微软雅黑";} </style> <script type="text/javascript" src="https://api.map.baidu.com/api?v=2.0&ak=FB33d26d18536d1ee0712c4f01bf2123&s=1"></script> <title>经纬度算两点距离-百度api-精确度第一</title> </head> <body> <div id="allmap"></div> </body> </html> <script type="text/javascript"> // 百度地图API功能 var map = new BMap.Map("allmap"); // 创建Map实例 var point1 = new BMap.Point(116.357428, 39.90923); var point2 = new BMap.Point(116.397428, 39.90923); var distance =map.getDistance(point1, point2); console.log(distance) </script>
二、经纬度算两点距离-误差2米-精确度第二
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" > <head runat="server"> <title>经纬度算两点距离-误差2米-精确度第二</title> <script type="text/javascript"> var DEF_PI = 3.14159265359; // PI var DEF_2PI = 6.28318530712; // 2*PI var DEF_PI180 = 0.01745329252; // PI/180.0 var DEF_R = 6370693.5; // radius of earth function getShortDistance(lon1, lat1, lon2, lat2) { var ew1, ns1, ew2, ns2; var dx, dy, dew; var distance; // 角度转换为弧度 ew1 = lon1 * DEF_PI180; ns1 = lat1 * DEF_PI180; ew2 = lon2 * DEF_PI180; ns2 = lat2 * DEF_PI180; // 经度差 dew = ew1 - ew2; // 若跨东经和西经180 度，进行调整 if (dew > DEF_PI) dew = DEF_2PI - dew; else if (dew < -DEF_PI) dew = DEF_2PI + dew; dx = DEF_R * Math.cos(ns1) * dew; // 东西方向长度(在纬度圈上的投影长度) dy = DEF_R * (ns1 - ns2); // 南北方向长度(在经度圈上的投影长度) // 勾股定理求斜边长 distance = Math.sqrt(dx * dx + dy * dy).toFixed(0); console.log(distance) return distance; } getShortDistance(116.357428,39.90923,116.397428,39.90923) </script> </head> <body> </body> </html>
三、经纬度算两点距离-误差4米-精确度第三
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" > <head runat="server"> <title>经纬度算两点距离-误差4米-精确度第三</title> <script type="text/javascript"> function distanceByLnglat(lng1,lat1,lng2,lat2) { var radLat1 = Rad(lat1); var radLat2 = Rad(lat2); var a = radLat1 - radLat2; var b = Rad(lng1) - Rad(lng2); var s = 2 * Math.asin(Math.sqrt(Math.pow(Math.sin(a / 2), 2) + Math.cos(radLat1) * Math.cos(radLat2) * Math.pow(Math.sin(b / 2), 2))); s = s * 6378137.0;// 取WGS84标准参考椭球中的地球长半径(单位:m) s = Math.round(s * 10000) / 10000; alert(s); // //下面为两点间空间距离（非球面体） // var value= Math.pow(Math.pow(lng1-lng2,2)+Math.pow(lat1-lat2,2),1/2); // alert(value); } function Rad(d) { return d * Math.PI / 180.0; } </script> </head> <body> <form id="form1" runat="server"> <div onclick ="distanceByLnglat(116.357428, 39.90923,116.397428, 39.90923);"> test me </div> </form> </body> </html>
四、经纬度算两点距离-误差1000米-精确度第四
<!DOCTYPE html> <html> <head> <meta charset="UTF-8"> <title>经纬度算两点距离-误差1000米-精确度第四</title> </head> <body> </body> <script type="text/javascript"> var EARTH_RADIUS = 6378137.0; //地球半径 var PI = Math.PI; function getRad(d){ return d*PI/180.0; } function getFlatternDistance(lat1,lng1,lat2,lng2){ var f = getRad((lat1 + lat2)/2); var g = getRad((lat1 - lat2)/2); var l = getRad((lng1 - lng2)/2); var sg = Math.sin(g); var sl = Math.sin(l); var sf = Math.sin(f); var s,c,w,r,d,h1,h2; var a = EARTH_RADIUS; var fl = 1/298.257; sg = sg*sg; sl = sl*sl; sf = sf*sf; s = sg*(1-sl) + (1-sf)*sl; c = (1-sg)*(1-sl) + sf*sl; w = Math.atan(Math.sqrt(s/c)); r = Math.sqrt(s*c)/w; d = 2*w*a; h1 = (3*r -1)/2/c; h2 = (3*r +1)/2/s; var dis=d*(1 + fl*(h1*sf*(1-sg) - h2*(1-sf)*sg)); console.log(dis); return dis; } getFlatternDistance(116.357428,39.90923,116.397428,39.90923) </script> </html>
五、经纬度算两点距离-误差1000米-精确度第五
<!DOCTYPE html> <html> <head> <meta charset="UTF-8"> <title>经纬度算两点距离-误差1000米-精确度第五</title> </head> <body> </body> <script type="text/javascript"> var EARTH_RADIUS = 6378137.0; //地球半径 var PI = Math.PI; function getRad(d){ return d*PI/180.0; } function getGreatCircleDistance(lat1,lng1,lat2,lng2){ var radLat1 = getRad(lat1); var radLat2 = getRad(lat2); var a = radLat1 - radLat2; var b = getRad(lng1) - getRad(lng2); var s = 2*Math.asin(Math.sqrt(Math.pow(Math.sin(a/2),2) + Math.cos(radLat1)*Math.cos(radLat2)*Math.pow(Math.sin(b/2),2))); s = s*EARTH_RADIUS; s = Math.round(s*10000)/10000.0; console.log(s); return s; } getGreatCircleDistance(116.357428,39.90923,116.397428,39.90923) </script> </html>
