自己偶尔看到了下图。于是用php打印出下图。

                      

两种方法解决此问题:

     方法一:依据图分析该图是一个二维数组,可用二维数组解决此类问题,6行就是6个数组,每一行就代表数组有多少个元素。知道每一个数组元素的个数。不就能够知道数组中有哪几个元素吗?

           

function array_chunk_vertical($arr, $colun)
{
    $arr_length = count($arr);
    $parem = floor($arr_length / $colun);
    $pare = $arr_length % $colun;
    $ar = array();
    for ($i = 0; $i < $colun; $i ++) {
        $par = $i == $colun - 1 ? 1 : 5;
        $ar[] = $par;
    }
    $newarray = array();
    foreach ($ar as $value) {
        for ($i = 0; $i < $value; $i ++) {
            $newarray[$i][] = array_shift($arr);
        }
    }
    return $newarray;
}

$arr = range(1, 31);
$data = array_chunk_vertical($arr, 7);
foreach ($data as $value) {
    foreach ($value as $va) {
        printf('[%2s]', $va);
    }
    echo "<br/>";
}

方法二:如代码。先给出size个空数组。在空数组中填充元素。

详细方法例如以下:

<?

php function array_chunk_vertical($input, $size, $preserve_keys = FALSE, $size_is_horizontal = false) { $chunks = array(); if ($size_is_horizontal) { $chunk_count = ceil(count($input) / $size); } else { $chunk_count = $size; } for ($chunk_index = 0; $chunk_index < $chunk_count; $chunk_index++) { $chunks[] = array(); } $chunk_index = 0; foreach ($input as $key => $value) { if ($preserve_keys) { $chunks[$chunk_index][$key] = $value; } else { $chunks[$chunk_index][] = $value; } if (++$chunk_index == $chunk_count) { $chunk_index = 0; } } return $chunks; } $data=range(1,31); $newdata=array_chunk_vertical($data,6); foreach ($newdata as $root){ foreach ($root as $val){ printf('[%2s]',$val); } echo "<br/>"; }


posted on 2017-07-22 21:23  lxjshuju  阅读(143)  评论(0编辑  收藏  举报