python课后实验（5）

课后第5次实验

1、

ls = [['Name','Age','Gender'],
['Bob','10','male'],
['Ala','12','female'],
['Cindy','12','female'],
['Dan','13','male']]

f=open("out.csv","w")
for l in ls:
    s=','.join(l)+'\n'
    f.write(s)
f.close()

 

2、

f = open('out.csv','r')
maxlen=0
maxS=''
for line in f.readlines():
    if len(line)>maxlen:
        line=line.replace('\n','')
        maxlen=len(line)
        maxS=line
print(maxS)
f.close()

 

3、

fo = open('data.csv','r')
ls = f.readlines()
ls = ls[::-1]
lt = []
for item in ls:
    item = item.replace("\n","")
    item = item.replace(" ","")
    Is = item.split(",")
    lt = lt[::1]
    print(";".joiin(it))
f.close()

 

4、

f = open("阶乘.txt"，"w")
t = 1
for i in range(1,101):
    t = t*i
    f.write(str(i)+"!="+str(t)+"\n")
f.close()

 

5、

def lsprime(n):
    for i in range(2,n):
        if n%i==0:
            return False
    return True

f=open("素数.txt","r")
count = 0
s = 0
for line in f:
    a = line.split(",")
    for j in range(len(a)):
        a[j]=a[j].replace(" ","")
        if a[j]>'0':#全都在对数据进行处理
            if lsprime(eval(a[j])):
                count = count +1
                s = s+eval(a[j])
f.close()
print("有{}个质数，他们的和是{}".format(count,s))

 

6、

def check():
    if  x*x+y*y==z*z or x*x+z*z==y*y or x*x==y*y+z*z:
        return Ture
    else:
        return False
        
f = open("整数.txt",'r')
count = 0

for line in f.readlines():
    line=line.replace('\n','')
    a=line.split(',')
    if len(a)==3:
        x=eval(a[0])
        y=eval(a[1])
        z=eval(a[2])
        if x>0 and y>0 and z>0:
            if check(x,y,z)==True:
                count = count + 1
                print(x,y,z)
f.close()
print('共有{}组数据可以构成直角三角形'.format(count))

 

7、

f = open('整数.txt','r')
count = 0
a,b,c,max=0,0,0,0
for line in f:
    line=line.replace('\n','')
    d=line.split(',')
    if len(d)==3:
        x=eval(d[0])
        y=eval(d[1])
        z=eval(d[2])
        if x>0 and y>0 and z>0 and x+y>z and x+z>y and y+z>x:
            p=(x+y+z)/2
            s=(p*(p-x)*(p-y)*(p-z))**0.5
            if s>max:
                max=s
                a,b,c=x,y,z
f.close()
print('最大面积为{:.2f},边长分别{},{},{}.format(max,a,b,c)')