[leetcode] Remove Linked List Elements

Remove Linked List Elements

Remove all elements from a linked list of integers that have value val.

Example
Given: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6
Return: 1 --> 2 --> 3 --> 4 --> 5

Credits:
Special thanks to @mithmatt for adding this problem and creating all test cases.

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/**
* Definition for singly-linked list.
* struct ListNode {
*     int val;
*     ListNode *next;
*     ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution
{
public:
  ListNode* removeElements(ListNode *head, int val)
  {
    ListNode *pre_ptr = NULL, *cur_ptr = head;

    while(cur_ptr)
    {
      if(cur_ptr->val == val)
      {
        if(NULL == pre_ptr)
        {
          head = head->next;
          delete cur_ptr;
          cur_ptr = head;
        }
        else
        {
          pre_ptr->next = cur_ptr->next;
          delete cur_ptr;
          cur_ptr = pre_ptr->next;
        }
      }
      else
      {
        pre_ptr = cur_ptr;
        cur_ptr = cur_ptr->next;
      }
    }

    return head;
  }
};

 

posted @ 2015-05-05 16:16  imKirin  阅读(87)  评论(0编辑  收藏  举报