有Thread1、Thread2、Thread3、Thread4四条线程分别统计C、D、E、F四个盘的大小,所有线程都统计完毕交给Thread5线程去做汇总,应当如何实现?

利用java.util.concurrent包下的CountDownLatch(减数器)或CyclicBarrier(循环栅栏)

转自:http://www.cnblogs.com/westward/p/7144620.html

实现1:用concurrent包下的CountDownLatch

/**
 * 假如有Thread1、Thread2、Thread3、Thread4四条线程分别统计C、D、E、F四个盘的大小,所有线程都统计完毕交给Thread5线程去做汇总,应当如何实现?
 * 本例,用CountDownLatch实现,CountDownLatch相当于一个计时器
 * */

public class Test1_1 {
    
    public static void main(String[] args) throws InterruptedException {
        //创建一个能容纳4个线程的减数器
        final CountDownLatch countDownLatch= new CountDownLatch(4);
        Runnable run1= new Runnable() {
            
            @Override
            public void run() {
                try {
                    Thread.sleep(3000);
                    System.out.println("统计C盘");
                    countDownLatch.countDown();//单任务,把计数器减1
                } catch (InterruptedException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }
            }
        };
        Runnable run2= new Runnable() {
            
            @Override
            public void run() {
                try {
                    Thread.sleep(3000);
                    System.out.println("统计D盘");
                    countDownLatch.countDown();
                } catch (InterruptedException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }
            }
        };
        Runnable run3= new Runnable() {
            
            @Override
            public void run() {
                try {
                    Thread.sleep(3000);
                    System.out.println("统计E盘");
                    countDownLatch.countDown();
                } catch (InterruptedException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }
            }
        };
        Runnable run4= new Runnable() {
            
            @Override
            public void run() {
                try {
                    Thread.sleep(3000);
                    System.out.println("统计F盘");
                    countDownLatch.countDown();
                } catch (InterruptedException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }
            }
        };
        
        ExecutorService service= Executors.newFixedThreadPool(4);
        service.submit(run1);
        service.submit(run2);
        service.submit(run3);
        service.submit(run4);
        /*new Thread(run1).start();
        new Thread(run2).start();
        new Thread(run3).start();
        new Thread(run4).start();*/
        
        countDownLatch.await();//主线程,即第5线程等待
        System.out.println("合计C,D,E,F");
        service.shutdown();

实现2:用concurrent包下的CyclicBarrier

/**
 * 假如有Thread1、Thread2、Thread3、Thread4四条线程分别统计C、D、E、F四个盘的大小,所有线程都统计完毕交给Thread5线程去做汇总,应当如何实现?
 * 本例,用CyclicBarrier实现,CyclicBarrier相当于一个栅栏,会将线程挡住
 * */

public class Test1_2 {
    public static void main(String[] args) {
        Runnable barrierAction= new Runnable() {
            
            @Override
            public void run() {
                System.out.println("统计C,D,E,F盘");
            }
        };
        
        final CyclicBarrier cyclicBarrier= new CyclicBarrier(4, barrierAction );
        Runnable run1= new Runnable() {
            
            @Override
            public void run() {
                try {
                    Thread.sleep(3000);
                    System.out.println("C盘");
                    cyclicBarrier.await();
                } catch (InterruptedException e) {
                    e.printStackTrace();
                } catch (BrokenBarrierException e) {
                    e.printStackTrace();
                }
                
            }
        };
        Runnable run2= new Runnable() {
            
            @Override
            public void run() {
                try {
                    Thread.sleep(3000);
                    System.out.println("D盘");
                    cyclicBarrier.await();
                } catch (InterruptedException e) {
                    e.printStackTrace();
                } catch (BrokenBarrierException e) {
                    e.printStackTrace();
                }
                
            }
        };
        Runnable run3= new Runnable() {
            
            @Override
            public void run() {
                try {
                    Thread.sleep(3000);
                    System.out.println("E盘");
                    cyclicBarrier.await();
                } catch (InterruptedException e) {
                    e.printStackTrace();
                } catch (BrokenBarrierException e) {
                    e.printStackTrace();
                }
                
            }
        };
        Runnable run4= new Runnable() {
            
            @Override
            public void run() {
                try {
                    Thread.sleep(3000);
                    System.out.println("F盘");
                    cyclicBarrier.await();
                } catch (InterruptedException e) {
                    e.printStackTrace();
                } catch (BrokenBarrierException e) {
                    e.printStackTrace();
                }
                
            }
        };
        
        ExecutorService service= Executors .newFixedThreadPool(4);
        service.submit(run1);
        service.submit(run2);
        service.submit(run3);
        service.submit(run4);
        service.shutdown();
        
        
    }
}

 

posted @ 2017-08-26 21:36  如果屈原会编程  阅读(476)  评论(0编辑  收藏  举报