作业四.

1.简单购物车,要求如下：

实现打印商品详细信息，用户输入商品名和购买个数，则将商品名，价格，购买个数加入购物列表，如果输入为空或其他非法输入则要求用户重新输入

msg_dic={'apple':10,'tesla':100000,'mac':3000,'lenovo':30000,'chicken':10,}
g = []
while True:
    for key,item in msg_dic.items():
        print('name:{name} price:{price}'.format(price=item,name=key))
    choice=input('商品>>:').strip()
    if not choice or choice not in msg_dic:continue
    count=input('购买个数>>:').strip()
    if not count.isdigit():continue
    g.append((choice,msg_dic[choice],count))
    print(g)

2.有如下值集合 [11,22,33,44,55,66,77,88,99,90...]，将所有大于 66 的值保存至字典的第一个key中，将小于 66 的值保存至第二个key的值中

即： {'k1': 大于66的所有值, 'k2': 小于66的所有值}

a={'k1':[],'k2':[]}
c=[11,22,33,44,55,66,77,88,99,90]
for i in c:
    if i>66:
        a['k1'].append(i)
    else:
        a['k2'].append(i)
print(a)

3.统计s='hello alex alex say hello sb sb'中每个单词的个数

结果如：{'hello': 2, 'alex': 2, 'say': 1, 'sb': 2}

s='hello alex alex say hello sb sb'
dic={}
words=s.split()
words_set=set(words)
for word in words_set:
    dic[word]=s.count(word)
    print(dic)

4.pythons={'alex','egon','yuanhao','wupeiqi','gangdan','biubiu'}

　　linuxs={'wupeiqi','oldboy','gangdan'}

1.pythons={'alex','egon','yuanhao','wupeiqi','gangdan','biubiu'}
linuxs={'wupeiqi','oldboy','gangdan'}
print(pythons & linuxs)

2.pythons={'alex','egon','yuanhao','wupeiqi','gangdan','biubiu'}

linuxs={'wupeiqi','oldboy','gangdan'}
print(pythons | linuxs)

3.pythons={'alex','egon','yuanhao','wupeiqi','gangdan','biubiu'}

linuxs={'wupeiqi','oldboy','gangdan'}
print(pythons - linuxs)

4.pythons={'alex','egon','yuanhao','wupeiqi','gangdan','biubiu'}

linuxs={'wupeiqi','oldboy','gangdan'}
print(pythons - linuxs^linuxs - pythons)


5.有列表l=['a','b',1,'a','a']，列表元素均为可hash类型，去重，得到新列表,且新列表无需保持列表原来的顺序

l=['a','b',1,'a','a']
new=list(set(l))
print(new)

l=[1,'a','b',1,'a']

l1=[]
for i in l:
    if i not in l1:
        l1.append(i)
print(l1)

s=set()
l1=[]
for item in l:
    val=(item['name'],item['age'],item['sex'])
    if val not in s:
        s.add(val)
        l1.append(item)

print(l1)