摘要: #includeint main(void){ int i,j,n,temp; int a[6][6]; printf("Enter n:"); scanf("%d",&n); for(i=0;i<n;i++) for(j=0;j<n;j++) a[i][j]=i*n+j+1; for(i=0;i<n;i++) for(j=0;j<n;j++) if(i<=j){ temp=a[i][j]; ... 阅读全文
posted @ 2013-10-06 16:03 吕鼎鼎19950427 阅读(78) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ int i,j; int a[3][2]; for(i=0;i<3;i++) for(j=0;j<2;j++) a[i][j]=i+j; for(i=0;i<3;i++){ for(j=0;j<2;j++) printf("%4d",a[i][j]); } return 0;} 阅读全文
posted @ 2013-10-06 15:44 吕鼎鼎19950427 阅读(127) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ int col,i,j,row; int a[3][2]; printf("Enter 6 integers:\n"); for(i=0;ia[row][col]){ row=i; col=j; } printf("max=a[%d][%d]=%d\n",row,col,a[row][col]); return 0;} 阅读全文
posted @ 2013-10-06 15:40 吕鼎鼎19950427 阅读(113) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ int a[10]={1,2,3,4,5,6,7,8,9,10}; int low,high,mid,n=10,x; printf("Enter x:"); scanf("%d",&x); low=0;high=n-1; while(low<=high){ mid=(low+high)/2; if(x==a[mid]) break; else if(x<a[mid]) high=mid-1; else ... 阅读全文
posted @ 2013-10-06 15:33 吕鼎鼎19950427 阅读(119) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ int i,index,k,n,temp; int a[10]; printf("Enter n:"); scanf("%d",&n); printf("Enter %d integers:",n); for(i=0;i<n;i++) scanf("%d",&a[i]); for(k=0;k<n-1;k++){ index=k; for(i=k+1;i<n;i++) if(a[i]<a[index]) index =i; ... 阅读全文
posted @ 2013-10-06 15:25 吕鼎鼎19950427 阅读(123) 评论(0) 推荐(0) 编辑
摘要: 阅读全文
posted @ 2013-10-06 15:16 吕鼎鼎19950427 阅读(100) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ int i,flag,x; int a[5]; printf("Enter 5 integers:"); for(i=0;i<5;i++) scanf("%d",&a[i]); printf("Enter x:"); scanf("%d",&x); flag=0; for(i=0;i<5;i++) if(a[i]==x){ printf("Index is %d\n",i); flag=1; bre... 阅读全文
posted @ 2013-10-06 15:10 吕鼎鼎19950427 阅读(90) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ int i; int fib[10]={1,1}; for(i=2;i<10;i++) fib[i]=fib[i-1]+fib[i-2]; for(i=0;i<10;i++){ printf("%6d",fib[i]); if((i+1)%5==0) printf("\n"); } return 0;} 阅读全文
posted @ 2013-10-06 15:03 吕鼎鼎19950427 阅读(82) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ int count[9]; int i,response; for(i=1;i8) printf("this is a bad response:%d\n",response); else count[response]++; } printf("result:\n"); for(i=1;i<=8;i++) printf("%4d%4d\n",i,count[i]); return 0;} 阅读全文
posted @ 2013-10-06 13:59 吕鼎鼎19950427 阅读(111) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ char ch; printf("input character:"); ch=getchar(); while(ch!='\n'){ if(ch>='A'&&ch='a'&&ch<='z') ch=ch-'a'+'A'; putchar(ch); ch=getchar(); } return 0;} 阅读全文
posted @ 2013-10-06 13:52 吕鼎鼎19950427 阅读(115) 评论(0) 推荐(0) 编辑