http://poj.org/problem?id=1008&lang=default&change=true

这个题倒是不难,就是麻烦一点,但是还WA了几次都是因为处理天数的时候没处理好,因为Haab这个日历日期是从0开始的,所以当第一年的最后一天第364天,而如果输入的恰好是365天应该是第二年的,所以,那个天数要放在下面处理

 

 

 1 #include<cstdio>
 2 #include<cstring>
 3 #include<iostream>
 4 using namespace std ;
 5 int main()
 6 {
 7     int n ;
 8     scanf("%d",&n) ;
 9     printf("%d\n",n);
10     for(int i = 1 ; i <= n ; i++)
11     {
12         int day,year ;
13         char month[11];
14         scanf("%d",&day) ;
15         getchar();
16         cin>>month ;
17         cin>>year ;
18         int mon ;
19         if(strcmp(month,"pop")==0) mon = 1 ;
20         if(strcmp(month,"no")==0) mon = 2 ;
21         if(strcmp(month,"zip")==0) mon = 3 ;
22         if(strcmp(month,"zotz")==0) mon = 4 ;
23         if(strcmp(month,"tzec")==0) mon = 5 ;
24         if(strcmp(month,"xul")==0) mon = 6 ;
25         if(strcmp(month,"yoxkin")==0) mon = 7 ;
26         if(strcmp(month,"mol")==0) mon = 8 ;
27         if(strcmp(month,"chen")==0) mon = 9 ;
28         if(strcmp(month,"yax")==0) mon = 10 ;
29         if(strcmp(month,"zac")==0) mon = 11 ;
30         if(strcmp(month,"ceh")==0) mon = 12 ;
31         if(strcmp(month,"mac")==0) mon = 13 ;
32         if(strcmp(month,"kankin")==0) mon = 14 ;
33         if(strcmp(month,"muan")==0) mon = 15 ;
34         if(strcmp(month,"pax")==0) mon = 16 ;
35         if(strcmp(month,"koyab")==0) mon = 17 ;
36         if(strcmp(month,"cumhu")==0) mon = 18 ;
37         if(strcmp(month,"uayet")==0) mon = 19 ;
38         int days = (year*365)+(mon-1)*20+day;
39         printf("%d ",days%260%13+1);
40         int Tdays = days%260%20+1 ;
41         if(Tdays == 1) cout<<"imix";
42         if(Tdays == 2) cout<<"ik";
43         if(Tdays == 3) cout<<"akbal";
44         if(Tdays == 4) cout<<"kan";
45         if(Tdays == 5) cout<<"chicchan";
46         if(Tdays == 6) cout<<"cimi";
47         if(Tdays == 7) cout<<"manik";
48         if(Tdays == 8) cout<<"lamat";
49         if(Tdays == 9) cout<<"muluk";
50         if(Tdays == 10) cout<<"ok";
51         if(Tdays == 11) cout<<"chuen";
52         if(Tdays == 12) cout<<"eb";
53         if(Tdays == 13) cout<<"ben";
54         if(Tdays == 14) cout<<"ix";
55         if(Tdays == 15) cout<<"mem";
56         if(Tdays == 16) cout<<"cib";
57         if(Tdays == 17) cout<<"caban";
58         if(Tdays == 18) cout<<"eznab";
59         if(Tdays == 19) cout<<"canac";
60         if(Tdays == 20) cout<<"ahau";
61         //int Tyears = (year*365)/260 ;
62         int Tyears = days/260;
63         cout<<" "<<Tyears<<endl ;
64     }
65     return 0 ;
66 }
View Code

 

posted on 2013-08-01 14:41  枫、  阅读(155)  评论(0编辑  收藏  举报