POJ 2586
把题读明白,列上几个式子就懂了,模拟就行
#include <iostream>
#include <algorithm>
#include <cstring>
#include <vector>
#include <cmath>
using namespace std;
int main() {
int s,d;
int res = 0;
while(cin >> s >> d) {
if(d > 4 * s) res = 10 * s - 2 * d;
else if(2 * d > 3 * s) res = 8 * s - 4 * d;
else if(3 * d > 2 * s) res = 6 * (s - d);
else if(4 * d > s) res = 3 * (s - 3 * d);
else res = -1;
if(res < 0) cout << "Deficit" << endl;
else cout << res << endl;
}
return 0;
}
参考