Palindrome Partitioning

Palindrome Partitioning 

Given a string s, partition s such that every substring of the partition is a palindrome.

Return all possible palindrome partitioning of s.

For example, given s = "aab",
Return

  [
    ["aa","b"],
    ["a","a","b"]
  ]
参考了这个锅锅的，思路很清晰，用的类似DFS递归实现http://www.sjsjw.com/kf_code/article/033776ABA018056.asp


 1 import java.util.ArrayList;
 2 import java.util.List;
 3 
 4 public class Solution {
 5     
 6     public List<List<String>> partition(String s) {
 7         List<List<String>> result = new ArrayList<List<String>>();            //存放结果
 8         List<String> curList = new ArrayList<String>();                        //记录当前结果
 9         
10         if(s.length() == 0)
11             return result;
12         getResult(result, curList, s);
13         
14         return result;
15     }
16     
17     /**
18      * 判断字符串是否为回文
19      * @param str
20      * @return
21      */
22     public boolean isPalindrom(String str){
23         for(int i = 0, j = str.length() - 1; i < j; i++, j--){
24             if(str.charAt(i) != str.charAt(j))
25                 return false;
26         }
27         
28         return true;
29     }
30     
31     /**
32      * 递归调用
33      * @param curList
34      * @param str
35      */
36     public void getResult(List<List<String>> result,List<String> curList, String str){
37         if(str.length() == 0)
38             result.add(new ArrayList<String>(curList));                //满足条件添加到结果集中,注意这里因为curList是引用，必须new一个新的list出来
39         else{
40             for(int i = 1; i <= str.length();i++){
41                 String head = str.substring(0, i);
42                 if(isPalindrom(head)){                                //子串是回文
43                     curList.add(head);
44                     getResult(result, curList, str.substring(i));
45                     curList.remove(curList.size() - 1);
46                 }
47             }
48         }
49     }
50 //    public void show(List<List<String>> list){
51 //        for(List<String> list_temp : list){
52 //            for(String string_temp : list_temp){
53 //                System.out.print(string_temp + " ");
54 //            }
55 //            System.out.println();
56 //        }
57 //    }
58 }

 

posted on 2014-12-24 20:39  luckygxf  阅读(180)  评论(0)  编辑  收藏  举报

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