Compare Version Numbers

Compare Version Numbers 

Compare two version numbers version1 and version1.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37
 1 public class Solution {
 2     public int compareVersion(String version1, String version2) {        
 3         String ver1_ch[] = version1.split("\\.");
 4         String ver2_ch[] = version2.split("\\.");
 5                
 6         int i = 0;
 7         for(; i < ver1_ch.length && i <ver2_ch.length; i++){
 8             
 9             if(Integer.valueOf(ver1_ch[i]) > Integer.valueOf(ver2_ch[i]))
10                 return 1;
11             else if(Integer.valueOf(ver1_ch[i]) < Integer.valueOf(ver2_ch[i]))
12                 return -1;
13         }
14         if(i >= ver1_ch.length && i >= ver2_ch.length)
15             return 0;
16         else if(i >= ver1_ch.length){
17             for(; i < ver2_ch.length; i++){
18                 if(Integer.valueOf(ver2_ch[i]) > 0)
19                     return -1;
20             }
21             return 0;
22         }
23         else
24         {
25             for(; i < ver1_ch.length; i++){
26                 if(Integer.valueOf(ver1_ch[i]) > 0)
27                     return 1;
28             }
29             return 0;
30         }
31     }
32 }

 

posted on 2014-12-16 20:29  luckygxf  阅读(262)  评论(0编辑  收藏  举报

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