字符串全排列

    public void perm(char[] chs, int start, List<String > res) {
        if (start == chs.length - 1) {
            res.add(new String(chs));
        } else {
            for (int i = start; i < chs.length; i++) {
                swapChs(chs, start, i);
                perm(chs, start + 1, res);
                swapChs(chs, start, i);
            }
        }
    }

    private void swapChs(char[] chs, int i, int j) {
        char temp = chs[i];
        chs[i] = chs[j];
        chs[j] = temp;
    }

 

posted on 2021-05-23 15:21  luckygxf  阅读(80)  评论(0编辑  收藏  举报

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