HDU2602-Bone Collector

描述：

　　Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave … 

　　The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ? 

 

　　The first line contain a integer T , the number of cases. 

　　Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.

　　One integer per line representing the maximum of the total value (this number will be less than 2 ³¹).

代码：

　　最基本的01背包。

#include<stdio.h>
#include<string.h>
#include<iostream>
#include<stdlib.h>
#include <math.h>
using namespace std;
#define N 1005

int main(){
    int T,n,v;
    int worth[N],cost[N],dp[N];
    scanf("%d",&T);
    while( T-- ){
        scanf("%d%d",&n,&v);
        for( int i=1;i<=n;i++ )
            scanf("%d",&worth[i]);
        for( int i=1;i<=n;i++ )
            scanf("%d",&cost[i]);
        memset(dp,0,sizeof(dp));
        for( int i=1;i<=n;i++ ){
            for( int j=v;j>=cost[i];j-- ){
                dp[j]=max(dp[j],dp[j-cost[i]]+worth[i]);
            }
        }
        printf("%d\n",dp[v]);
    }
    system("pause");
    return 0;
}