摘要: int n1; int n2; int n3; printf("n1 address is %p\n",&n1); printf("n2 address is %p\n",&n2); printf("n3 address is %p\n",&n3); n1 address is 0xbffdd468 阅读全文
posted @ 2021-09-29 01:53 MikeLi 阅读(36) 评论(0) 推荐(0) 编辑