tuple 方法总结整理
#!/usr/bin/env python #Python 3.7.0 元祖常用方法 __author__ = "lrtao2010" #元祖和列表类似,只不过元祖一旦被创建一级元素不可更改(增删改)。 # a = ('123',['abc'],'b',345,['6','7','d'],) # a[-1][2] = 'c' # print(a) # a[-1].append(123) # print(a) # ('123', ['abc'], 'b', 345, ['6', '7', 'c']) # ('123', ['abc'], 'b', 345, ['6', '7', 'c', 123]) # a = ('123',['abc'],'b',345,['6','7','d'],) # a[0] = '456' # print(a) # a[0] = '456' # TypeError: 'tuple' object does not support item assignment #a = ('123','a',123,['a','b','c'],) #元祖最后一个元素后面一般加上','号 # a = ('123',['abc'],'b',345,['6','7','d'],) # v1 = a[1] # v2 = a[2:] # v3 = a[1:-1] # print(v1) # print(v2) # print(v3) # ['abc'] # ('b', 345, ['6', '7', 'd']) # (['abc'], 'b', 345) #可迭代 # a = ('123',['abc'],'b',345,['6','7','d'],) # for i in a: # print(i) # # 123 # ['abc'] # b # 345 # ['6', '7', 'd'] #count 统计指定值出现的次数 # a = ('a','b','a',['a','b','ab'],'ab',) # v1 = a.count('a') # v2 = a[3].count('b') # print(v1,v2) # 2 1 # index(self, *args, **kwargs)查找指定值的位置,不存在会报错 # a = ('a','b') # v = a.index('b') # print(v) # 1