【openjudge 计算概论（A）】[结构体与链表练习]

#include<cstdio>
#include<string>
#include<cstring>
#include<iostream>
#include<algorithm>
using namespace std;
struct ch{
    string name;
    int yue,day,len;
}child[200];
int tmp(ch a,ch b)
{
  if (a.yue<b.yue) return 1;
  if (a.yue>b.yue) return 0;
  if (a.day<b.day) return 1;
  if (a.day>b.day) return 0;
  if (a.len<b.len) return 1;
  if (a.len>b.len) return 0;
  if (a.name<b.name) return 1;
  return 0;
}
int n;
int main()
{
    int i;
    bool t=0;
    scanf("%d",&n);
    for (int i=1;i<=n;i++)
     {
        cin>>child[i].name;
        child[i].len=child[i].name.length();
        scanf("%d%d",&child[i].yue,&child[i].day);
     }
    sort(child+1,child+n+1,tmp);
    i=1;
    while(i<=n)
     {
      if (child[i].yue==child[i+1].yue&&child[i].day==child[i+1].day)
       {
         t=1;
         printf("%d %d ",child[i].yue,child[i].day);
         cout<<child[i].name<<' ';
         int a,b;
         a=child[i].yue; b=child[i].day;
         i++;
         while(child[i].yue==a&&child[i].day==b)
          cout<<child[i++].name<<' ';
         printf("\n");
       }
       else ++i;
     }
    if (!t) printf("None\n");
    return 0;
}

#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
int n,a[200010],x;
int main()
{
  int i;
  scanf("%d",&n);
  for (i=1;i<=n;++i) scanf("%d",&a[i]);
  scanf("%d",&x);
  for (i=1;i<=n;++i)
   if (a[i]!=x)
     printf("%d ",a[i]);
  return 0;
}

[不会链表！拒绝链表！]

3:统计学生信息（使用动态链表完成）

#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
using namespace std;
char s[11100][210];
int top;
int main()
{
 int i;
 while(gets(s[++top]));
 top-=2;
 for (i=top;i>=1;i--)
  printf("%s\n",s[i]);
 return 0;
}

[这样良心的题为什么要搞链表。。。]