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【openjudge 计算概论(A)】[指针练习]

#include<cstdio>
using namespace std;
int a[110],n;
int main()
{
 int i;
 scanf("%d",&n);
 for (i=1;i<=n;i++)
  scanf("%d",&a[i]);
 for (i=n;i>0;i--)
  printf("%d ",a[i]);
 return 0;
}


#include<cstdio>
#include<cstring>
using namespace std;
int maxn,tm,n,len;
char s[210];
int main()
{
    int i,j;
    scanf("%d",&n);
    for (i=1;i<=n;++i)
     {
        int t=1;
        scanf("%s",s);
        len=strlen(s);
        for (j=1;j<len;++j)
         if (s[j]==s[j-1]) t++;
          else
           if (t>maxn) maxn=t,tm=s[j-1],t=1;
            else t=1;
        if (t>maxn) maxn=t,tm=s[len-1];
        printf("%c %d\n",tm,maxn);
        maxn=tm=0;
     }
    return 0;
}


#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
char s[100010];
int n,len,last;
int main()
{
 int i,j,k;
 scanf("%d\n",&n);
 gets(s);
 len=strlen(s);
 i=0;j=1;
 while(i<len)
  {
    while(i<len&&j<=80)
     ++i,++j;
    while(s[i]!=' '&&i!=len)
     i--,j--;
    for (k=last;k<i;++k)
     printf("%c",s[k]);
    last=i+1;
    printf("\n");
    j=0;
  }
}

#include<cstdio>
#include<cstring>
using namespace std;
int k,n,m;
long long ans;
int main()
{
    int i,j,t;
    scanf("%d",&k);
    for (t=1;t<=k;++t)
     {
        scanf("%d%d",&m,&n);
        for (i=1;i<=m;i++)
         for (j=1;j<=n;++j)
          {
            long long x;
            scanf("%lld",&x);
            if(i==1||i==m||j==1||j==n) ans+=x;
           }
        printf("%lld\n",ans);
        ans=0;
     }
    return 0;
}

#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
int a[110][110],n,m;
bool p[110][110];
int main()
{
	int i,j;
	scanf("%d%d",&n,&m);
	for(i=1;i<=n;++i)
	 for(j=1;j<=m;++j)
	  scanf("%d",&a[i][j]);
	for(i=1;i<=n;++i)
	 for(j=1;j<=m;++j)
	  if(!p[i][j])
      {
      	int x=i,y=j;
      	while(x<=n&&y) printf("%d\n",a[x][y]),p[x++][y--]=1;
	  }
	return 0;
}



posted @ 2016-10-16 11:41  lris0-0  阅读(152)  评论(0编辑  收藏  举报
过去的终会化为美满的财富~o( =∩ω∩= )m