【hdu 2669】Romantic（扩展欧几里得）

Romantic

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 5424    Accepted Submission(s): 2287

Problem Description

The Sky is Sprite.
The Birds is Fly in the Sky.
The Wind is Wonderful.
Blew Throw the Trees
Trees are Shaking, Leaves are Falling.
Lovers Walk passing, and so are You.
................................Write in English class by yifenfei



Girls are clever and bright. In HDU every girl like math. Every girl like to solve math problem!
Now tell you two nonnegative integer a and b. Find the nonnegative integer X and integer Y to satisfy X*a + Y*b = 1. If no such answer print "sorry" instead.

 

Input

The input contains multiple test cases.
Each case two nonnegative integer a,b (0<a, b<=2^31)

 

Output

output nonnegative integer X and integer Y, if there are more answers than the X smaller one will be choosed. If no answer put "sorry" instead.

 

Sample Input

77 51 10 44 34 79

 

Sample Output

2 -3 sorry 7 -3

 

Author

yifenfei

 

Source

HDU女生专场公开赛——谁说女子不如男

 

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【题解】【扩展欧几里得】

#include<cstdio>
#include<cstring>
#include<algorithm>
#define ll long long
using namespace std;
ll a,b,ans;
ll gcd(ll a,ll b,ll &x,ll &y)
{
	if(!b) {x=1; y=0; return a;}
	ll d=gcd(b,a%b,x,y);
	ll t=x; x=y; y=t-a/b*y;
	return d;
}
inline ll exgcd(ll a,ll b,ll c)
{
	ll x,y;
	ll d=gcd(a,b,x,y);
	if(c%d) return -1;
	x*=c/d; b/=d;
	if(b<0) b=-b;
	ll sum=x%b;
	if(sum<=0) sum+=b;
	return sum; 
}
int main()
{
	while(scanf("%I64d%I64d",&a,&b)==2)
	 {
	 	ans=exgcd(a,b,1);
	 	if(ans==-1) {printf("sorry\n"); continue;}
	 	printf("%I64d %I64d\n",ans,(1-ans*a)/b);
	 }
}