Oracle数据库学习（6）子查询
概述：在查询时基于未知的值时，可以使用子查询。
1、查询工资比Abel高的员工
SELECT LAST_NAME,SALARY FROM EMPLOYEES WHERE SALARY>(SELECT SALARY FROM EMPLOYEES WHERE LAST_NAME='Abel')
2、查询员工名为Chen的manage的信息
SELECT EMPLOYEE_ID,LAST_NAME,SALARY FROM EMPLOYEES WHERE EMPLOYEE_ID=(SELECT MANAGER_ID FROM EMPLOYEES WHERE LAST_NAME='Chen')
3、查询job_id与员工id为141号的员工相同，salary比143号员工多的员工，job_id和工资
SELECT LAST_NAME,JOB_ID,SALARY FROM EMPLOYEES WHERE JOB_ID=(SELECT JOB_ID FROM EMPLOYEES WHERE EMPLOYEE_ID=141)
AND SALARY>(SELECT SALARY FROM EMPLOYEES WHERE EMPLOYEE_ID=143)
4、查询最低工资大于50号部门最低工资的部门id和其最低工资
SELECT DEPARTMENT_ID,MIN(SALARY) FROM EMPLOYEES GROUP BY DEPARTMENT_ID
HAVING MIN(SALARY)>(SELECT MIN(SALARY) FROM EMPLOYEES WHERE DEPARTMENT_ID=50)
5、查询和Zlotkey相同部门的员工姓名和雇用日期
select last_name,hire_date from employees where department_id = (select department_id from employees where last_name = 'Zlotkey')
and last_name <> 'Zlotkey'
6、查询各部门中工资比本部门平均工资高的员工的员工号, 姓名和工资
select employee_id,last_name,salary from employees e1 where salary > (select avg(salary) from employees e2 where e1.department_id = e2.department_id group by department_id)
7、查询和姓名中包含字母u的员工在相同部门的员工的员工号和姓名
select employee_id,last_name from employees where department_id in (select department_id from employees
where last_name like '%u%') and last_name not like '%u%';
8、查询在部门的location_id为1700的部门工作的员工的员工号
select employee_id from employees where department_id in (select department_id from departments where location_id = 1700)
9、查询管理者是King的员工姓名和工资
select last_name,salary from employees where manager_id in (select employee_id from employees where last_name = 'King')
10、查询员工的last_name, department_id, salary.其中员工的salary,department_id与有奖金的任何一个员工的salary,department_id相同即可
select last_name,department_id,salary from employees where (salary,department_id) in
(select salary,department_id from employees where commission_pct is not null )
11、选择工资大于所有JOB_ID = 'SA_MAN'的员工的工资的员工的last_name, job_id, salary
select last_name,job_id,salary from employees
where salary > all(select salary from employees where job_id = 'SA_MAN')
12、 选择所有没有管理者的员工的last_name
select last_name from employees e1
where not exists (select 'A' from employees e2 where e1.manager_id = e2.employee_id)
