采用C/C++语言如何实现复数抽象数据类型Complex

记录一下！

采用C/C++语言如何实现复数抽象数据类型Complex

#include <stdio.h>
 
typedef struct Complex
{
    double e1; // 实部
    double e2; // 虚部
 
}COMPLEX;
 
// 函数声明
COMPLEX AssignComplex(double v1, double v2);
void DestroyComplex(COMPLEX pc);
double GetReal(COMPLEX pc);
double GetImag(COMPLEX pc);
COMPLEX Add(COMPLEX z1, COMPLEX z2);
 
 
int main(void)
{
    double v1 = 2.0, v2 = 3.0;
    double v3 = 5.0, v4 = 8.5;
    COMPLEX sum;
    COMPLEX pc1 = AssignComplex(v1, v2);
    COMPLEX pc2 = AssignComplex(v3, v4);
 
    printf("第一个复数的实部为：%e, 虚部为：%e\n", GetReal(pc1), GetImag(pc1));
 
    sum = Add(pc1, pc2);
    printf("复数pc1与pc2之和的实部为：%e，虚部为：%e\n", sum.e1, sum.e2);
    return 0;
}
 
 
COMPLEX AssignComplex(double v1, double v2)
{
    COMPLEX pc;
    pc.e1 = v1;
    pc.e2 = v2;
    return pc;
}
void DestroyComplex(COMPLEX pc)
{
    // 销毁复数
}
double GetReal(COMPLEX pc)
{
    double real = pc.e1;
    return real;
}
 
double GetImag(COMPLEX pc)
{
    double imag = pc.e2;
    return imag;
}
COMPLEX Add(COMPLEX z1, COMPLEX z2)
{
    COMPLEX sum;
    double z1_e1, z2_e1;
    double z1_e2, z2_e2;
 
    z1_e1 = z1.e1;
    z2_e1 = z2.e1;
 
    z1_e2 = z1.e2;
    z2_e2 = z2.e2;
 
    sum.e1 = z1_e1 + z2_e1;
    sum.e2 = z1_e2 + z2_e2;
 
    return sum;
}