oracle如何去除字符串中的重复字符
1 create or replace function remove_rame_string(oldStr varchar2, sign varchar2) 2 return varchar2 is 3 4 /**************************************************** 5 ** Oracle去掉重复字符串 6 ** 函数名称:RemoveSameStr 7 ** 参 数:【名称】 【类型 】 【说明】 8 ** oldStr varchar2 要处理的字符串 9 ** sign varchar2 字符串分隔符 10 ** 返 回 值:Result varchar2 不包含重复子串的记录 11 ****************************************************/ 12 str varchar2(2000); 13 currentIndex number; 14 startIndex number; 15 endIndex number; 16 17 type str_type is table of varchar2(30) index by binary_integer; 18 arr str_type; 19 Result varchar2(1000); 20 begin 21 -- 空字符串 22 if oldStr is null then 23 return(''); 24 end if; 25 26 --字符串太长 27 if length(oldStr) > 2000 then 28 return(oldStr); 29 end if; 30 str := oldStr; 31 32 currentIndex := 0; 33 startIndex := 0; 34 35 loop 36 currentIndex := currentIndex + 1; 37 endIndex := instr(str, sign, 1, currentIndex); 38 if (endIndex <= 0) then 39 exit; 40 end if; 41 42 arr(currentIndex) := trim(substr(str, 43 startIndex + 1, 44 endIndex - startIndex - 1)); 45 startIndex := endIndex; 46 end loop; 47 48 --取最后一个字符串: 49 arr(currentIndex) := substr(str, startIndex + 1, length(str)); 50 51 --去掉重复出现的字符串: 52 for i in 1 .. currentIndex - 1 loop 53 for j in i + 1 .. currentIndex loop 54 if arr(i) = arr(j) then 55 arr(j) := ''; 56 end if; 57 end loop; 58 end loop; 59 60 str := ''; 61 for i in 1 .. currentIndex loop 62 if arr(i) is not null then 63 str := str || sign || arr(i); 64 --数组置空: 65 arr(i) := ''; 66 end if; 67 end loop; 68 69 --去掉前面的标识符: 70 Result := substr(str, 2, length(str)); 71 72 return(Result); 73 end remove_rame_string;
create or replace function remove_rame_string(oldStr varchar2, sign varchar2, newStr varchar2) return varchar2 is /**************************************************** ** Oracle去掉重复字符串 ** 函数名称:RemoveSameStr ** 参 数:【名称】 【类型 】 【说明】 ** oldStr varchar2 要处理的字符串 ** sign varchar2 字符串分隔符 ** newStr varchar2 新添加的字符串,以逗号隔开 ** 返 回 值:Result varchar2 不包含重复子串的记录 ****************************************************/ str varchar2(2000); currentIndex number; startIndex number; endIndex number; type str_type is table of varchar2(30) index by binary_integer; arr str_type; Result varchar2(1000); begin -- 空字符串 if oldStr is null then return('[' || newStr || ']'); end if; --字符串太长 if length(oldStr) > 2000 then return(oldStr); end if; str := oldStr; --拼接字符串,在"]"之前添加新创建的字符串 str := substr(str, 0, instr(str, ']')-1) || ','||newStr; str := substr(str, instr(str, '[')+1, length(str)); currentIndex := 0; startIndex := 0; loop currentIndex := currentIndex + 1; endIndex := instr(str, sign, 1, currentIndex); if (endIndex <= 0) then exit; end if; arr(currentIndex) := trim(substr(str, startIndex + 1, endIndex - startIndex - 1)); startIndex := endIndex; end loop; --取最后一个字符串: arr(currentIndex) := substr(str, startIndex + 1, length(str)); --去掉重复出现的字符串: for i in 1 .. currentIndex - 1 loop for j in i + 1 .. currentIndex loop if arr(i) = arr(j) then arr(j) := ''; end if; end loop; end loop; str := ''; for i in 1 .. currentIndex loop if arr(i) is not null then str := str || sign || arr(i); --数组置空: arr(i) := ''; end if; end loop; --去掉前面的标识符: Result := substr(str, 2, length(str)); return('[' || Result || ']'); end remove_rame_string; UPDATE TEST_CLOB set "STR" = remove_rame_string(STR, ',', '"str1","str2", "str2", "str3"') WHERE ID='1';
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