摘要: <%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%><%String path = request.getContextPath();String basePath = request.getScheme()+":/ 阅读全文
posted @ 2017-12-04 22:59 can丶 阅读(143) 评论(0) 推荐(0) 编辑
摘要: <html> <head> </head> <frameset rows="80,*"> <frame src="index_stu_title.jsp" scrolling="no"> <frameset cols="140,*"> <frame src="index_stu_left.jsp" 阅读全文
posted @ 2017-12-03 22:55 can丶 阅读(410) 评论(0) 推荐(0) 编辑
摘要: <%@ page language="java" import="java.sql.*" contentType="text/html;charset=utf-8"%> <% String path = request.getContextPath(); String basePath = requ 阅读全文
posted @ 2017-11-29 22:51 can丶 阅读(287) 评论(0) 推荐(0) 编辑
摘要: <%@ page language="java" import="java.sql.*" contentType="text/html;charset=utf-8"%> <% String path = request.getContextPath(); String basePath = requ 阅读全文
posted @ 2017-11-28 22:42 can丶 阅读(527) 评论(0) 推荐(0) 编辑
摘要: <%@ page language="java" import="java.util.*" contentType="text/html;charset=utf-8"%> <% String path = request.getContextPath(); String basePath = req 阅读全文
posted @ 2017-11-27 22:10 can丶 阅读(323) 评论(0) 推荐(0) 编辑
摘要: #include <stdio.h>int fun( int *b ){ int k,a1,a2,i=0; for(k=10; k<=55; k++) {a2=k/10; a1=k-a2*10; if((k%3==0 && a2==5)||(k%3==0 && a1==5)) { b[i]=k; i 阅读全文
posted @ 2017-11-26 22:27 can丶 阅读(894) 评论(0) 推荐(0) 编辑
摘要: <%@ page language="java" import="java.util.*" contentType="text/html;charset=utf-8"%> <html> <head> <title> 用户登录 </title> </head> <body bgcolor="#e3e3 阅读全文
posted @ 2017-11-24 22:58 can丶 阅读(308) 评论(0) 推荐(0) 编辑
摘要: #include <stdio.h>int c1,c2,c3;void fun(long n){ c1=c2=c3=0; while(n) { switch(n%10) { case 1: c1++;break; case 2: c2++;break; case 3: c3++; } n/=10; 阅读全文
posted @ 2017-11-23 21:12 can丶 阅读(2216) 评论(0) 推荐(0) 编辑
摘要: #include <stdio.h>#include <math.h> int fun( int high ){ int sum = 0, n=0, j, yes;while ((high>=2) && (n<10) { yes = 1; for (j=2; j<=high/2; j++ ) if 阅读全文
posted @ 2017-11-22 22:59 can丶 阅读(3775) 评论(0) 推荐(0) 编辑
摘要: #include <stdio.h>#include <math.h>int fun(int n,int *value){ int d,s,i;d=1;s=0; for(i=1;i<=5;i++) d=d*n; *value=d; for(i=1;i<=3;i++) { s=s+d%10;d=d/1 阅读全文
posted @ 2017-11-20 22:59 can丶 阅读(1501) 评论(0) 推荐(0) 编辑