摘要: #include <stdio.h>int c1,c2,c3;void fun(long n){ c1=c2=c3=0; while(n) { switch(n%10) { case 1: c1++;break; case 2: c2++;break; case 3: c3++; } n/=10; 阅读全文
posted @ 2017-11-23 21:12 can丶 阅读(2216) 评论(0) 推荐(0) 编辑