从xap文件中读取文件
2009-03-04 21:54 张智清 阅读(458) 评论(0) 编辑 收藏 举报读取图片文件:
SteamResourceInfo sri=Application.GetResourceStream(new Uri("filename;component/assets/"+dm.spic,UriKind.Relative));
BitmapImage bi=new BitmapImage();
bi.SetSource(sri.Stream);
Image img=new Image();
img.Source=bi;
BitmapImage bi=new BitmapImage();
bi.SetSource(sri.Stream);
Image img=new Image();
img.Source=bi;
读取XML文件并用Linq来初始化数据:
public void InitDataMode() {
StreamResouceInfo sri=Application.GetResourceStream(new Uri("filename;component/Data/DataModel.xml",UriKind.Relative));
XmlReader reader=XmlReader.Create(sri.Stream);
XDocument document=XDocument.Load(reader);
listData=(from c in document.Descendants("model")
select new DataModel
{
t1=c.Element("t1").Value,
t2=c.Element("t2").Value,
t3=c.Element("t3").Value,
url=c.Element("url").Value,
spic=c.Element("spic").Value,
bpic=c.Element("bpic").Value
}).ToList<DataModel>();
sri.Stream.Close();
sri.Stream.Dispose();
}
StreamResouceInfo sri=Application.GetResourceStream(new Uri("filename;component/Data/DataModel.xml",UriKind.Relative));
XmlReader reader=XmlReader.Create(sri.Stream);
XDocument document=XDocument.Load(reader);
listData=(from c in document.Descendants("model")
select new DataModel
{
t1=c.Element("t1").Value,
t2=c.Element("t2").Value,
t3=c.Element("t3").Value,
url=c.Element("url").Value,
spic=c.Element("spic").Value,
bpic=c.Element("bpic").Value
}).ToList<DataModel>();
sri.Stream.Close();
sri.Stream.Dispose();
}
注解:
StreamResourceInfo sri = Application.GetResourceStream(new Uri("{0};component/{1}", UriKind.Relative));
0为xap程序集的名字,
1为要读取的文件在在xap中的路径。